Pls help ASAP!! Pleaseee now!!

I need to finish this usa test prep now plz help

Slav-nsk [51]

Answer:

R = 101

S = 131

Step-by-step explanation:

First, you will want to get your angle T. Since T is on the same line as the angle with 128 degree, you can easily find angel T. They are supplementary angels and form 180.

T=180-128

T=52

You also know that all angles in a triangle equal to 180

Use that to find angle S

180 = R+S+T

180 = 79 + S + 52

180 - 79 - 52 = S

49 = S, exterior S = 180-49 = 131

Exterior R = 180 - 79 = 101

Now add all your exteriors

8 0

3 years ago

I AM VERY DESPERATE NOW!!! I HAVE ASKED THIS SAME QUESTION 3 TIMES AND NOBODY HAS BEEN ABLE TO ANSWER IT. PLEASE HELP, SOMEONE!!

Alexandra [31]

Answer:

Interest rate is 5.25% a year.

Step-by-step explanation:

r = (1/54)((22252.5/18000) - 1) = 0.004375

r = 0.004375

Convert decimal to percentage

R = 0.004375 * 100 = 0.4375%/month

Calculate annual rate

0.4375%/month × 12 months/year = 5.25% per year.

8 0

3 years ago

Read 2 more answers

Fill in the blank to make it a true statement: 50 ___ |-50|

Sergeeva-Olga [200]

50, 0 ,|-50|
I don’t really have an explanation but that’s the answer

7 0

3 years ago

Using traditional methods it takes 92 hours to receive an advanced flying license. A new training technique using Computer Aided

DanielleElmas [232]

Answer:

The value of the test statistic is z = 1.39.

The p-value of the test is 0.0823 > 0.05, which means that there is not evidence at the 0.05 level that the technique lengthens the training time.

Step-by-step explanation:

Using traditional methods it takes 92 hours to receive an advanced flying license.

This means that at the null hypothesis, it is tested if the mean is of 92, that is:

$H_0: \mu = 92$

Test if there is evidence that the technique lengthens the training time

At the alternative hypothesis, it is tested if the mean is more than 92, that is:

$H_1: \mu > 92$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

92 is tested at the null hypothesis:

This means that $\mu = 92$

A researcher used the technique on 70 students and observed that they had a mean of 93 hours. Assume the population variance is known to be 36.

This means that $n = 70, X = 93, \sigma = \sqrt{36} = 6$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{93 - 92}{\frac{6}{\sqrt{70}}}$

$z = 1.39$

The value of the test statistic is z = 1.39.

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 93, which is 1 subtracted by the p-value of z = 1.39.

Looking at the z-table, z = 1.39 has a p-value of 0.9177.

1 - 0.9177 = 0.0823.

The p-value of the test is 0.0823 > 0.05, which means that there is not evidence at the 0.05 level that the technique lengthens the training time.

8 0

3 years ago

I need answers and reasoning <br> On 14 plz include a drawing

otez555 [7]

Answer:

Yes, it doubles.

Step-by-step explanation:

2 times 8.6 is 17.2

it doubles because of the ratio the sides of a rite triangle are in. the ratio is always the same

7 0

3 years ago