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AnnyKZ [126]
3 years ago
6

Solve the system of equations. 2x+2y+7z=9, 2x+6y+5z=7, 5x+2y+4z=9. a.x=3 y=-2 z=3 b.x=1 y=0 z=1 c.x=2 y=-1 z=0 d. x=0 y=1 z=2

Mathematics
1 answer:
ki77a [65]3 years ago
6 0
The answer is B

Hope this helps.
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What is the difference of the polynomials?
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3 years ago
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3 years ago
Read 2 more answers
I need help learning how to solve this problem please.
Radda [10]

we have 4 gals, Stephanie, Andrea, Emily and  Becca.

btw the end point should be (-6, -7) and the start point is (8, 6).

so, if we know the distance between those two points, we can just cut it in 4 equal pieces and each gal will be driving a piece.

now, Emily's turn is after Andrea, BUT, we had first Stephenie driving ¼ of the way, then Andrea driving ¼ of the way too, but after ¼+¼, Emily comes on, but ¼+¼ is really 1/2, so when Emily starts, is really half-way through, or the midpoint of that distance.


\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
\stackrel{\textit{Hometown}}{(\stackrel{x_1}{8}~,~\stackrel{y_1}{6})}\qquad
\stackrel{\textit{San Antonio}}{(\stackrel{x_2}{-6}~,~\stackrel{y_2}{-7})}
\qquad
\left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{-6+8}{2}~~,~~\cfrac{-7+6}{2} \right)\implies \left(\cfrac{2}{2}~,~\cfrac{-1}{2} \right)\implies \stackrel{\textit{Emily starts off}}{\left(1~,-\frac{1}{2} \right)}


Emily's turn ends ¼ of the way later, which will be pretty much half-way in between  (1, -½) and (-6, -7), so is really the midpoint of those two.


\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
(\stackrel{x_1}{1}~,~\stackrel{y_1}{-\frac{1}{2}})\qquad
\stackrel{\textit{San Antonio}}{(\stackrel{x_2}{-6}~,~\stackrel{y_2}{-7})}
\\\\\\
\left( \cfrac{-6+1}{2}~~,~~\cfrac{-7-\frac{1}{2}}{2} \right)\implies \left( \cfrac{-5}{2}~,~\cfrac{~\frac{-14-1}{2}~}{2} \right)\implies \left( \cfrac{-5}{2}~,~\cfrac{~\frac{-15}{2}~}{2} \right)
\\\\\\
\left( \cfrac{-5}{2}~,~\cfrac{-15}{4} \right)\implies \left( -2\frac{1}{2}~,~-3\frac{3}{4} \right)

8 0
3 years ago
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