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pogonyaev
3 years ago
8

Find all possible values of the expression 1/y if: .125

Mathematics
1 answer:
34kurt3 years ago
8 0

Answer:

The possible values for 1/y of the expression 0.125 < y < 0.25 are in the range

4 < 1/y < 8

Step-by-step explanation:

The given information are;

The range of values of y are 0.125 < y < 0.25, therefore, we have;

The boundaries of the function, y are 0.125 and 0.25

The inverse of the boundaries of the function, y are 1/0.125 = 8 and 1/0.24 = 4

Therefore;

The limits of the inverse of the function y are ;

The inequality that represents 1/y is therefore;

1/0.25 < 1/y < 1/0.125 or 4 < 1/y < 8

The possible values of 1/y for the expression 0.125 < y < 0.25 are therefore;

4 < 1/y < 8.

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24/6+6

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3 years ago
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Find the product of this square of a binomial.<br> (2x - 3)^2
Scilla [17]

Answer:

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3 0
3 years ago
On a farm the number of cows and the number of sheep are in the tatio 6:5 the number of sheep and the number of pigs are in the
Rzqust [24]

Answer:

There are 70 sheep in the farm.

Step-by-step explanation:

Consider the provided information.

Let c represents the cows, s represents the sheep and p represents the pigs.

The number of cows and the number of sheep are in the ratio 6:5.

\dfrac{c}{s} =\dfrac{6}{5}

c =\dfrac{6s}{5}

The number of sheep and the number of pigs are in the ratio 2:1.

\dfrac{s}{p} =\dfrac{2}{1}

p =\dfrac{s}{2}

The total number is 189.

c+s+p=189

Substitute the value of c and p in above.

\dfrac{6s}{5}+s+\dfrac{s}{2}=189

\dfrac{12s+10s+5s}{10}=189

27s=1890

s=70

Hence, there are 70 sheep in the farm.

8 0
3 years ago
Find the approximate difference in the area of the two circles shown below. Use 3.14 for pi.
Kobotan [32]

Answer:

b answer

Step-by-step explanation:

8 0
3 years ago
DASAROLLA:<br><br>a) (x+3) (x+5)=<br><br>b) (x+4) (x-5)=​
Nat2105 [25]

Answer:

a)x^{2}+8x+15

b)x^{2}-x-20

Step-by-step explanation:

a) (x+3)(x+5)

a)x^{2}+5x+3x+15

a)x^{2}+8x+15

b) (x+4)(x-5)

b) x^{2}-5x+4x-20

b)x^{2}-x-20

8 0
3 years ago
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