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wlad13 [49]
3 years ago
9

Given a matrix input_matrix, return a Numpy array that consists of every entry of A that has: an even row index in the range [0,

7) an odd column index in the range [3, 8) This can be accomplished in a single line.
def PROBLEM3 (input_matrix):
# YOUR CODE GOES HERE
return output_matrix
# DO NOT MODIFY
np.random.seed (3251)
example = np.random.randint(0, 10, (10,10))
print(example)
print(PROBLEM3 (example))
Computers and Technology
1 answer:
ipn [44]3 years ago
6 0

Answer:

range [0, 7) an odd column index in the range [3, 8) This can be accomplished in a single line.

def PROBLEM3 (input_matrix):

# YOUR CODE GOES HERE

return output_matrix

# DO NOThern bus under

You might be interested in
Edhesive AP Computer Science Coding Activity 2:
Romashka-Z-Leto [24]

Answer:

The method in C++ is as follows:

double average(int v, int w, int x, int y, int y){

   double ave = (v+w+x+y+z)/5.0;

   return ave;

}

Explanation:

This defines the average method with 5 parameters

double average(int v, int w, int x, int y, int y){

This calculates the average

   double ave = (v+w+x+y+z)/5.0;

This returns the calculated average

   return ave;

}

To call the method from the program's main, use:

<em>int main(){</em>

<em>    cout<<average(1,5,7,4,10);</em>

<em>    return 0;</em>

<em>}</em>

<em />

7 0
3 years ago
Write an if-else statement with multiple branches. If givenYear is 2101 or greater, print "Distant future" (without quotes). Els
kherson [118]

Answer:

// here is code in c.

#include <stdio.h>

// main function

int main()

{

// variable to store year

int year;

printf("enter year:");

// read the year

scanf("%d",&year);

// if year>=2101

if(year>=2101)

{

printf("Distant future");

}

//if year in 2001-2100

else if(year>=2001&&year<=2100)

{

   printf("21st century");

}

//if year in 19011-2000

else if(year>=1901&&year<=2000)

{

  printf("20th century");

}

// if year<=1900

else if(year<=1900)

{

  printf("Long ago");  

}

return 0;

}

Explanation:

Read the year from user.After this, check if year is greater or equal to 2101 then print "Distant future".If year is in between 2001-2100 then print "21st century".If year is in between 1901-2000 then print "20th century".Else if year is less or equal to 1900 then print "Long ago".

Output:

enter year:2018                                                                                                            

21st century

7 0
3 years ago
Read 2 more answers
A pedometer treats walking 2,000 steps as walking 1 mile. Write a program whose input is the number of steps, and whose output i
Amanda [17]

Answer:

import java.util.Scanner;

public class num1 {

   public static void main(String[] args) {

   Scanner in = new Scanner(System.in);

   //Prompt and receive user input

       System.out.println("Enter number of Steps");

       int numSteps = in.nextInt();

       double numMiles = numSteps/2000;

       //Print the formated number of miles

       System.out.printf("The equivalent miles is %.2f ",numMiles);

   }

}

Explanation:

  • This is solved using Java programming language
  • Scanner class is imported and used to receive user input (number of steps walked)
  • To convert number of steps to number of miles, we divide by 2000, Since the question says the pedometer treats walking 2,000 steps as walking 1 mile.
  • Output the number of miles to 2 decimal places using java's printf() method
6 0
3 years ago
Read 2 more answers
Implement a method called bubbleSort, that takes an ArrayList, sorts it using bubble sort algorithm, and returns a sorted list;
boyakko [2]

Answer:

Java algorithm is given below

Explanation:

import java.util.ArrayList;

import java.util.Arrays;

import java.util.Random;

public class Temp {

   static void bubbleSort(ArrayList<Integer> list) {

       int n = list.size();

       for (int p = 0; p < n - 1; p++)

           for (int q = 0; q < n - p - 1; q++)

               if (list.get(q) > list.get(q + 1)) {

                   int temp = list.get(q);

                   list.set(q, list.get(q + 1));

                   list.set(q + 1, temp);

               }

   }

   static void selectionSort(ArrayList<Integer> list) {

       int n = list.size();

       for (int p = 0; p < n - 1; p++) {

           int minimumIndex = p;

           for (int q = p + 1; q < n; q++)

               if (list.get(q) < list.get(minimumIndex))

                   minimumIndex = q;

           int temp = list.get(p);

           list.set(p, list.get(minimumIndex));

           list.set(minimumIndex, temp);

       }

   }

   static void insertionSort(ArrayList<Integer> list) {

       int size = list.size();

       int p, val, q;

       for (p = 1; p < size; p++) {

           val = list.get(p);

           q = p - 1;

           while (q >= 0 && list.get(q) > val) {

               list.set(q + 1, list.get(q));

               q = q - 1;

           }

           list.set(q + 1, val);

       }

   }

   static void mergeSort(ArrayList<Integer> list, int low, int high) {

       if (low < high && (high - low) >= 1) {

           int mid = (high + low) / 2;

           mergeSort(list, low, mid);

           mergeSort(list, mid + 1, high);

           merger(list, low, mid, high);

       }

   }

   static void merger(ArrayList<Integer> list, int low, int mid, int high) {

       ArrayList<Integer> mergedArray = new ArrayList<Integer>();

       int left = low;

       int right = mid + 1;

       while (left <= mid && right <= high) {

           if (list.get(left) <= list.get(right)) {

               mergedArray.add(list.get(left));

               left++;

           } else {

               mergedArray.add(list.get(right));

               right++;

           }

       }

       while (left <= mid) {

           mergedArray.add(list.get(left));

           left++;

       }

       while (right <= high) {

           mergedArray.add(list.get(right));

           right++;

       }

       int i = 0;

       int j = low;

       while (i < mergedArray.size()) {

           list.set(j, mergedArray.get(i++));

           j++;

       }

   }

   public static void main(String[] args) throws Exception {

       ArrayList<Integer> list = new ArrayList<>();

       Random rand = new Random(System.currentTimeMillis());

       for (int i = 0; i < 10000; i++) {

           list.add(rand.nextInt(256));

       }

       long start = System.currentTimeMillis();

       selectionSort(list);

       int sel = (int) (System.currentTimeMillis() - start);

       System.out.println("Selection Sort time (in ms): " + sel);

       list.clear();

       // ------------------------

       rand = new Random(System.currentTimeMillis());

       for (int i = 0; i < 10000; i++) {

           list.add(rand.nextInt(256));

       }

       start = System.currentTimeMillis();

       insertionSort(list);

       int ins = (int) (System.currentTimeMillis() - start);

       System.out.println("Insertion Sort time (in ms): " + ins);

       list.clear();

       // ------------------------

       rand = new Random(System.currentTimeMillis());

       for (int i = 0; i < 10000; i++) {

           list.add(rand.nextInt(256));

       }

       start = System.currentTimeMillis();

       bubbleSort(list);

       int bub = (int) (System.currentTimeMillis() - start);

       System.out.println("Bubble Sort time (in ms): " + bub);

       list.clear();

       // ---------------------------

       rand = new Random(System.currentTimeMillis());

       for (int i = 0; i < 10000; i++) {

           list.add(rand.nextInt(256));

       }

       start = System.currentTimeMillis();

       mergeSort(list, 0, list.size() - 1);

       int mer = (int) (System.currentTimeMillis() - start);

       System.out.println("Merge Sort time (in ms): " + mer);

       long m = Math.min(Math.min(sel, ins), Math.min(bub, mer));

       if (m == sel)

           System.out.println("Selection Sort is fastest");

       else if (m == ins)

           System.out.println("insertion Sort is fastest");

       else if (mer == m)

           System.out.println("Merge Sort is fastest");

       else if (m == bub)

           System.out.println("Bubble Sort is fastest");

   }

}

6 0
3 years ago
The high-latitude climate is _____________ the equator.<br><br> closest to<br> farthest from
BARSIC [14]
I believe it’s farthest from
5 0
3 years ago
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