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Rzqust [24]
3 years ago
6

Can someone help me with this problem? Please.

Mathematics
1 answer:
Mamont248 [21]3 years ago
4 0

Answer:

(7x-1)-3(7x-1)

Step-by-step explanation:

First write out the problem

7x^2-22x+3

Next, Factor the expressions

7x^2 - x - 21x + 3

Now factor the whole thing

x(7x-1)-3(7x-1)

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find the equation of the circle where (-9,4),(-2,5),(-8,-3),(-1,-2) are the vertices of an inscribed square.
solniwko [45]
Check the picture below, so, that'd be the square inscribed in the circle.

so... hmm the diagonals for the square are the diameter of the circle, and keep in mind that the radius of a circle is half the diameter, so let's find the diameter.

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -2}}\quad ,&{{ 5}})\quad 
%  (c,d)
&({{ -8}}\quad ,&{{ -3}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
\stackrel{diameter}{d}=\sqrt{[-8-(-2)]^2+[-3-5]^2}
\\\\\\
d=\sqrt{(-8+2)^2+(-3-5)^2}\implies d=\sqrt{(-6)^2+(-8)^2}
\\\\\\
d=\sqrt{36+64}\implies d=\sqrt{100}\implies d=10

that means the radius r = 5.

now, what's the center?  well, the Midpoint of the diagonals, is really the center of the circle, let's check,

\bf \textit{middle point of 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -2}}\quad ,&{{ 5}})\quad 
%  (c,d)
&({{ -8}}\quad ,&{{ -3}})
\end{array}\qquad 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left( \cfrac{-8-2}{2}~,~\cfrac{-3+5}{2} \right)\implies (-5~,~1)

so, now we know the center coordinates and the radius, let's plug them in,

\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}\\
&-5&1&5
\end{array}
\\\\\\\
[x-(-5)]^2-[y-1]^2=5^2\implies (x+5)^2-(y-1)^2=25

8 0
3 years ago
yo i need help with this question please and thank u i need the correct answer to please i will give u a brainliest as well
Simora [160]
V = πr ^2 h
V = π (3)^2 (5)
V = π (9) (5)
V = π 45
V = 141.3 in
141.3 divided by 8 = 17.7
8 0
3 years ago
69 POINTS FOR THE BEST ANSWER EVER!! PLEASE HELP PRO'S are aloud!! :D<br><br><br> TYSM everyone
slava [35]
I would say a because it best fits 
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3 years ago
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Multiply out and simplify to obtain a minimum sum-of-products boolean expression:
max2010maxim [7]

Answer:

As per the question, we need to convert product of sum into sum of product,

Given:

(A' +B+C')(A'+C'+D)(B'+D'),

At first, we will solve to parenthesis,

= (A'+C'+BD) (B'+D')

As per the Rule, (A+B)(A+C) = A+BC, In our case if we assume X = A'+C', then,

(A' +B+C')(A'+C'+D) = (A'+C'+B)(A'+C'+D) = (A'+C'+BD)

Now,  

= (A'+C'+BD) (B'+D') = A'B' + A'D' + C'B' +C'D' +BDB' +BDD"

As we know that AA' =  0, it mean

=A'B'+A'D'+C'B'+C'D'+D*0+B0

=A'B'+A'D'+C'B'+C'D'               as B * 0 and D*0 = 0

Finally, minimum sum of product boolean expression is

A''B'+A'D'+C'B'+C'D'

=

5 0
3 years ago
Solve the following 2(x+3)=x-4
USPshnik [31]
2x + 6 = x - 4
x = -10
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