So, to factorise something you are taking out the highest common factor.Here, 10 is an example of the highest common factor (I’ll refer to this as HCF)
10(2k+5)
Everything inside the brakets is multiplied by what’s directly next to it (if there is a negative sign, then that is included). So, 10 x 2k = 20k and 10 x 5 = 50
10(2k + 5) is the factorised version of 20k + 50
We have been given an expression . We are asked to choose the expressions, which are equivalent to our given expression.
Using exponent property , we can rewrite our given expression as:
Upon looking at our given choices, we can see that option D is the correct choice.
Let us simplify our given expression.
Upon cancelling out from numerator and denominator, we will get:
Using exponent property , we will get:
Therefore, option B is a correct choice as well.
Step-by-step explanation:
- <em>-x-4=</em><em>4</em><em>x</em><em>-</em><em>5</em><em>4</em>
Adding x on both sides, we get
- <em>-x-4+</em><em>x=</em><em>4</em><em>x</em><em>-</em><em>5</em><em>4</em><em>+</em><em>x</em>
- <em>-</em><em>4</em><em>=</em><em>5</em><em>x</em><em>-</em><em>5</em><em>4</em>
Adding 54 on both sides, we get
- <em>-</em><em>4</em><em>+</em><em>5</em><em>4</em><em>=</em><em>5</em><em>x</em><em>-</em><em>5</em><em>4</em><em>+</em><em>5</em><em>4</em>
- <em>5</em><em>0</em><em>=</em><em>5</em><em>x</em>
Dividing both sides by 5, we get
- <em>5</em><em>0</em><em>/</em><em>5</em><em>=</em><em>5</em><em>x</em><em>/</em><em>5</em>
- <em>1</em><em>0</em><em>=</em><em>x</em>
<em>Hence,</em><em> </em><em>the </em><em>value</em><em> of</em><em> x</em><em> </em><em>is</em><em> </em><em>1</em><em>0</em><em>.</em>
'll use the binomial approach. We need to calculate the probabilities that 9, 10 or 11
<span>people have brown eyes. The probability that any one person has brown eyes is 0.8, </span>
<span>so the probability that they don't is 1 - 0.8 = 0.2. So the appropriate binomial terms are </span>
<span>(11 C 9)(0.8)^9*(0.2)^2 + (11 C 10)(0.8)^10*(0.2)^1 + (11 C 11)(0.8)^11*(0.2)^0 = </span>
<span>0.2953 + 0.2362 + 0.0859 = 0.6174, or about 61.7 %. Since this is over 50%, it </span>
<span>is more likely than not that 9 of 11 randomly chosen people have brown eyes, at </span>
<span>least in this region. </span>
<span>Note that (n C r) = n!/((n-r)!*r!). So (11 C 9) = 55, (11 C 10) = 11 and (11 C 0) = 1.</span>
218they are the annnns erv