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3 years ago

Multiply 4/5 by the reciprocal of −2/10.

Mathematics

2 answers:

Svetach [21]3 years ago

7 0

Answer:

4/5*reciprocal of -2/10

The reciprocal of -2/10 is 10/-2

4/5*10/2

Cancelling the numbers

-4 is the answer

Step-by-step explanation:

I hope it will help you :)

dybincka [34]3 years ago

5 0

Answer:

10/-2*4/5

40/-10=4/-1

4/-1=-4

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Find the indicated function values for the function below<br> g(x)=9x + 8<br> g(0) =

Dennis_Churaev [7]

Answer:

$g(0) = 8$

Step-by-step explanation:

The problem gives us the following function:

$g(x) = 9x + 8$

g(0) =

This is the value of g when x = 0. So

$g(x) = 9x + 8$

$g(0) = 9*0 + 8$

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So the answer to this question is:

$g(0) = 8$

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3 years ago

In a recent study, volunteers who had 8 hours of sleep were three times more likely to answer questions correctly on a math tes

Shalnov [3]

Answer:

Step-by-step explanation:

Sleep Deprivation

In a recent study, volunteers who had 8 hours of sleep were three times more likely to answer correctly on a math test than were sleep-deprived participants.

(a) Identify the sample used in the study.

(b) What is the sample's population?

(d) Make an inference based on the results of the study?

Solution

A. The samples used is the hours of sleep and math test scores of the volunteers

B. The samples population is hours of sleep and math test scores of people in general

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3 years ago

Find the domain of the function y = 3 tan(23x)

solmaris [256]

Answer:

$\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

In other words, the $x$ in $f(x) = 3\, \tan(23\, x)$ could be any real number as long as $x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)$ for all integer $k$ (including negative integers.)

Step-by-step explanation:

The tangent function $y = \tan(x)$ has a real value for real inputs $x$ as long as the input $x \ne \displaystyle k\, \pi + \frac{\pi}{2}$ for all integer $k$ .

Hence, the domain of the original tangent function is $\mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

On the other hand, in the function $f(x) = 3\, \tan(23\, x)$ , the input to the tangent function is replaced with $(23\, x)$ .

The transformed tangent function $\tan(23\, x)$ would have a real value as long as its input $(23\, x)$ ensures that $23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2}$ for all integer $k$ .

In other words, $\tan(23\, x)$ would have a real value as long as $x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right)$ .

Accordingly, the domain of $f(x) = 3\, \tan(23\, x)$ would be $\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

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2 years ago