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irina [24]
3 years ago
6

Find the total area of a round section of land that has a 2.5 foot wide enclosure of pebbles surrounding a round garden of flowe

rs.
Mathematics
1 answer:
Elena-2011 [213]3 years ago
5 0

Answer:

Step-by-step explanation:

Since the land is a round enclosure, and it has 2.5 foot wide enclosure of pebbles surrounding, then the circumference of the garden is 2.5ft.

First we need to get the diameter of the garden using the formula;

Circumference= πd

2.5 = πd

d = 2.5/π

d = 2.5/3.142

d =0.796 feet

The total area of a round section of the land = πd²/4

The total area of a round section of the land = π(0/796)²/4

The total area of a round section of the land  = 1.9892/4

<em>The total area of a round section of the land  = 0.4973 ft²</em>

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Ainat [17]
We can model the equation:y = m x + b, where y is the total profit and x is the number of hotdogs sold.The system of equations is:
90 = 40 m + b210 = 80 m + b---------------------b = 90 - 40 m210 = 80 m + 90 - 40 m210 - 90 = 40 m120 = 40 mm = 120 : 40m = 3b = 90 - 40*3b = 90 - 120b = - 30Answer: The equation is y = 3 x - 30

5 0
3 years ago
Rahima goes jogging on a course that is 2.75kilometers long. If she completes the full course every morning, how many kilometers
Arada [10]

Answer:

<h2>19.25km</h2>

Step-by-step explanation:

Step one:

given data

we are told that the distance that Rahima covers on a daily is 2.75km long

we also know that a week has 7 days that is Mon-Sunday

Required

the total distance for a week

Step two:

Hence the total distance covered for  7 days is

=2.75*7

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<em>Simply multiply the distance covered in a day by 7 to get the distance covered in a week </em>

6 0
2 years ago
Read 2 more answers
The equation of the graphed line is 2x-3y=12 what is the x-intercept of the graph ?
Natali [406]

Answer:

(6,0)

Step-by-step explanation:

7 0
3 years ago
Given the term 3x², select ALL of the like terms listed below. Question 3 options: A.-2x²
atroni [7]

Answer:

A.-2x^2

D.5x^2

E.x^2

Step-by-step explanation:

Like terms must have the same variable, in this case x, and the same exponent, in this case 2. Since the original term is 3x^2, the like terms will be those that contain x^2, regardless of whether their coefficient or sign is different.

Analyzing the options:

A.-2x^2

We have the same variable and the same exponent x^2, so it is a like term.

B. 3x

You have the same variable x but not the same exponent. So it's not a like term of 3x^2

C.3x^3

Same variable x but as in the previous case, the exponent is different, it is a 3 and it should be a 2, so it is not a similar or like term.

D.5x^2

In this option we do have the x^2, so it is a like term of  3x^2

E.x^2

It is also a like term because it contains the x^2.

In summary the like terms are:

A.-2x^2

D.5x^2

E.x^2

7 0
2 years ago
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Reika [66]
6-x=5x+30
+x. +x
6=6x+30
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3 years ago
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