Hello !
cos (a+b) = cos a cos b - sin a sin b
sin (a+b) = sin a cos b + sin b cos a
cos (a+b+c) = cos (a+(b+c))
cos (a+b+c) = cos a cos (b+c) - sin a sin (b+c)
cos (a+b+c) = cos a (cos b cos c - sin b sin c) - sin a (sin b cos c + sin c cos b)
cos (a+b+c)=cos a cos b cos c - cos a sin b sin c - sin a sin b cos c - sin a cos b sin c
9514 1404 393
Answer:
59) not similar
60)
Step-by-step explanation:
59) The ratios of the side lengths shown cannot be reduced. They are different, so the triangles are not similar.
7:8:12 ≠ 6:7:11
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60) The side length ratios both reduce to 8:7:10, so the triangles are similar.
∆ABC ~ ∆JKL
The scale factor is LJ/CA = 25/20 = 5/4. (Multiplying ABC by 5/4 will give JKL.)
3xy + 4x -16 ...... I hope that helps .
Answer:
A
Step-by-step explanation:
