Answer:
The answer is option (4) Maximize redundancy as normalization minimizes redundancy of data.
Explanation:
Normalization of databases leads to minimization of data redundancy in databases. It doesn't maximize data redundancy. Data redundancy leads to wastage of resources. Normalization of databases minimizes insertion anomolies. Normalization of databases minimizes deletion anomolies. Normalization of databases minimizes updation anomolies. So , the answer to the question is option (4) maximize redundancy.
Answer:
The answer is "The LMI model should be compatible with the supplier dynamically for the network manager".
Explanation:
The term LMI stands for the "Local Management Interface", it is a Cisco technology, in which the signaling protocol was used in between routers and transmission frame switches to share data in timekeepers, global addressing, multipathing as well as the present state of virtual socks for various purposes, in which it is mainly used for "dynamically setting, in which the network administrator provides compatibility with the service provider".
<span>C. 3
Due to the different speeds of P and S waves, a single seismometers can determine the distance to an earthquake. So, for a single station, the localization is any point on a circle around the station. With 2 stations, you'll have two circles that intersect at two points. The 3rd station is needed in order to determine which of the 2 points is the actual earthquake.</span>
Answer:
Predict Demand
Explanation:
The type of Artificial Intelligence (Al) solution that would be suitable for solving this problem is "Predict Deman"
By predicting the demand of the potential consumer through the Artificial intelligence solution the retailer would be able to eliminate leftover out-of-stock scenarios because the adequate quantity of the products or demands will be provided thereby enhancing customers' experience arising from out-of-stock scenarios and reducing losses arising from the leftover.
Answer:
highest of five numbers in the file
Explanation:
- This code reads the file "some-file.txt" and saves the result in variable "somefile"
- The runs a for loop for a count of 5.
- In each loop it compares the current value of the file with the value of the variable result and if the result is true it updates the value of the variable result.
- At the end of this code the variable result will contain the highest value in the file "some-file.txt" and print it.