Each junior receives 93 score on the test. It is also the average score of the juniors.
Given Information
It is given that 10% of the strength of the class consists of juniors and 90% consists of seniors.
Let us assume the total strength of the class is 100, then,
Number of seniors = 90
Number of juniors = 10
It is also given that the average score of the class = 84
And, average score of the seniors = 83
Another given information is that all the juniors all received the same score, which is their average score. Let it be x.
Average Score of Juniors
Total marks obtained by the seniors = Number of seniors × Average score of seniors
= 90 × 83
= 7470
Total marks obtained by the juniors = Number of juniors × Average score of juniors
= 10x
Average marks on the test = Total marks / Total number of students
⇒ 84 = (7470 + 10x)/100
⇒ 84 × 100 = 7470 + 10x
⇒ 10x + 7470 = 8400
⇒ 10x = 8400-7470
⇒ 10x = 930
⇒ x = 930/10
⇒ x = 93
Thus, each junior scores 93 on the test.
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Answer:
A histogram shows data that is skewed to the right. Which most likely describes the relationship between the mean and the median? The mean is greater than the median. The rightmost values in the data set raise the mean more than the median.
Answer:
3.47 and 3.21
Step-by-step explanation:
Let us assume the nails length be X
Value let separated the top 3% is T and for bottom it would be B
Now converting, we get
Based on the normal standard tables, we get
Now compare these two above equations
So for top 3% it is 3.47
Now for bottom we applied the same method as shown above
Based on the normal standard tables, we get
Now compare these two above equations
hence, for bottom it would be 3.21
Answer:
90
Step-by-step explanation:
Answer:
If you mean 4x to the power of 3 - 18x to the power of 2 +3x -13 then the answer is false
