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Anuta_ua [19.1K]
3 years ago
9

4232 divided by 18 also estimate

Mathematics
1 answer:
igomit [66]3 years ago
6 0
4232 divided by 18 equals 235.1
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Four goats eat 8 tin cans in one hour. How long should it take 8 goats to eat 4 tin cans?
quester [9]

Answer:

15

Step-by-step explanation:

15 minutes

8 0
3 years ago
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Root 8 + 3 root 32 - root 50
lisov135 [29]
\sqrt{8} + 3 \sqrt{32} - \sqrt{50}

= \sqrt{4 \times 2} + 3 \sqrt{16 \times 2} - \sqrt{25 \times 2}

= 2\sqrt{ 2} + 12 \sqrt{2} - 5\sqrt{  2}

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6 0
3 years ago
Daniel bought four bags of potatoes. The weight of the first bag was 2.6 pounds. The second bag weighed 0.4 pound less than twic
ipn [44]

Answer:

Average weight of the bags of potatoes is 3.8 pounds.

Step-by-step explanation:

Given:

Weight of the first bag, W_{1}=2.6 pounds.

Weight of the second bag is 0.4 pounds less than twice the weight of first bag. This means,

W_{2}=2W_{1}-0.4=2(2.6)-0.4=5.2-0.4=4.8\textrm{ pounds}

Weight of the third bag is 0.6 pounds more than that of the first bag. This means,

W_{3}=W_{1}+0.6=2.6+0.6=3.2\textrm{ pounds}

Weight of the fourth bag is 0.3 pounds less than that of the second bag. This means,

W_{4}=W_{2}-0.3=4.8-0.3=4.5\textrm{ pounds}

Therefore, the average weight of the bags of potatoes is given as the sum of all the weights and then divide the sum by 4. Therefore,

W_{average}=\frac{W_{1}+W_{2}+W_{3}+W_{4}}{4}=\frac{2.6+4.8+3.2+4.5}{2}=\frac{15.1}{4}=3.775\approx 3.8

Therefore, average weight of the bags of potatoes is 3.8 pounds.

8 0
3 years ago
I need help can someone help me pls
sattari [20]

Answer:

D: 25 miles

Step-by-step explanation:

Pythagorean Theorem:

a^{2} + b^2 = c^2

36^2 + b^2  =  39^2

1,296 + b^2  =  1,521

b^2  =  225

b  =  25

4 0
3 years ago
Which set of numbers could represent the lengths of the sides of a right triangle?
DiKsa [7]

Answer:

The first set: 8, 15, and 17.

Step-by-step explanation:

<h3>Pair: 8, 15, 17</h3>

By the pythagorean theorem, a triangle is a right triangle if and only if

\text{longest side}^2 = \text{first shorter side}^2 + \text{second shorter side}^2.

In this case,

\text{longest side}^2 = 17^2 = 289.

\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 8^2 + 15^2\\ &=64 + 225 = 289 \end{aligned}.

In other words, indeed \text{hypotenuse}^2 = \text{first leg}^2 + \text{second leg}^2. Hence, 8, 15, 17 does form a right triangle.

Similarly, check the other pairs. Keep in mind that the square of the longest side should be equal to the sum of the square of the two

<h3>Pair: 10, 15, 20</h3>

Factor out the common factor 2 to simplify the calculations.

\text{longest side}^2 = 20^2 = 400

\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 10^2 + 15^2\\ &=100 + 225 = 325 \end{aligned}.

\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2.

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

<h3>Pair: 12, 18, 22</h3>

\text{longest side}^2 = (2\times 11)^2 = 2^2 \times 121.

\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= (2 \times 6)^2 + (2 \times 9)^2\\ &=2^2 \times(36 + 81) = 2^2 \times 117 \end{aligned}.

\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2.

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

<h3>Pair: 7, 9, 11</h3>

\text{longest side}^2 = 11^2 = 121.

<h3>\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 7^2 + 9^2\\ &=49+ 81 = 130 \end{aligned}.</h3>

\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2.

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

6 0
4 years ago
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