Answer:
2,93x10³atmL, 2,97x10⁵J
Explanation:
The work done in gas compression under constant pressure is:
W = -P×ΔV
<em>Where W is work done, P is pressure and </em>ΔV <em>is change in volume (Vol.f - Vol.i)</em>
Replacing:
W = -61.0atm×(51.0L - 99.0L)
W = 2928atmL = <em>2,93x10³atmL</em>
In Joules:
2928atmL × (101,325J / 1atmL) = 296680J ≡<em> 2,97x10⁵J</em>
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I hope it helps!
Answer:
-) 3-bromoprop-1-ene
-) 2-bromoprop-1-ene
-) 1-bromoprop-1-ene
-) bromocyclopropane
Explanation:
In this question, we can start with the <u>I.D.H</u> (<em>hydrogen deficiency index</em>):
In the formula we have 3 carbons, 5 hydrogens, and 1 Br, so:
We have an I.D.H value of one. This indicates that we can have a cyclic structure or a double bond.
We can start with a linear structure with 3 carbon with a double bond in the first carbon and the Br atom also in the first carbon (<u>1-bromoprop-1-ene</u>). In the second structure, we can move the Br atom to the second carbon (<u>2-bromoprop-1-ene</u>), in the third structure we can move the Br to carbon 3 (<u>3-bromoprop-1-ene</u>). Finally, we can have a cyclic structure with a Br atom (<u>bromocyclopropane</u>).
See figure 1
I hope it helps!
Answer:
German chemist G.E. Stahl