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Verizon [17]
3 years ago
9

BRAINLIEST AND POINTS!!

Chemistry
2 answers:
artcher [175]3 years ago
8 0

Answer:

-Good writing explaining their data they have discovered

-Their research is shared with the other scientists, and is peer reviewed

-They present their results at national and international conferences where other scientists can listen and give their input.

Explanatio

umka21 [38]3 years ago
4 0

Answer:

There are several ways that scientists communicate our results, including written reports and scientific journal publications, and by giving presentations to our colleagues and the public. One popular venue for scientists to present to colleagues is at scientific conferences.

Explanation:

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The chemical formula for water is h2o. According to this formula what is the composition of a water molecule
sergejj [24]

Answer:

two hydrogen atoms and one oxygen atom

Explanation:

8 0
3 years ago
1.883 Grams of copper reacted with excess sulfur to form an unknown Copper sulfide. The reaction creates 2.308 grams of an unkno
rosijanka [135]

Answer:

um it is most likely copper

Explanation:

8 0
3 years ago
The hydrogen chloride (HCl) molecule has an internuclear separation of 127 pm (picometers). Assume the atomic isotopes that make
natta225 [31]

Answer:

the energy of the third excited rotational state \mathbf{E_3 = 16.041 \ meV}

Explanation:

Given that :

hydrogen chloride (HCl) molecule has an intermolecular separation of 127 pm

Assume the atomic isotopes that make up the molecule are hydrogen-1 (protium) and chlorine-35.

Thus; the reduced mass μ = \dfrac{m_1 \times m_2}{m_1 + m_2}

μ = \dfrac{1 \times 35}{1 + 35}

μ = \dfrac{35}{36}

∵ 1 μ = 1.66 × 10⁻²⁷ kg

μ  = \\ \\ \dfrac{35}{36} \times 1.66 \times 10^{-27} \ \  kg

μ  = 1.6139 × 10⁻²⁷ kg

r_o = 127 \ pm = 127*10^{-12} \ m

The rotational level Energy can be expressed by the equation:

E_J = \dfrac{h^2}{8 \pi^2 I } \times J ( J +1)

where ;

J = 3 ( i.e third excited state)  &

I = \mu r^2_o

E_J= \dfrac{h^2}{8  \pi  \mu r^ 2 \mur_o } \times J ( J +1)

E_3 = \dfrac{(6.63 \times 10^{-34})^2}{8  \times  \pi ^2  \times 1.6139 \times 10^{-27} \times( 127 \times 10^{-12}) ^ 2  } \times 3 ( 3 +1)

E_3= 2.5665 \times 10^{-21} \ J

We know that :

1 J = \dfrac{1}{1.6 \times 10^{-19}}eV

E_3= \dfrac{2.5665 \times 10^{-21} }{1.6 \times 10^{-19}}eV

E_3 = 16.041  \times 10 ^{-3} \ eV

\mathbf{E_3 = 16.041 \ meV}

8 0
3 years ago
✞What Is an Alloy?⭐⭐​
max2010maxim [7]
A alloy is a red chicken
8 0
3 years ago
How is the food in a stomach broken down into simpler substances? What chemicals help this process?
Ksenya-84 [330]

Answer:

with the help of the juice contained in it

4 0
3 years ago
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