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shepuryov [24]
3 years ago
10

Indicate which molecules demonstrate the correct bonding for carbon atoms. Check all that apply.

Chemistry
2 answers:
motikmotik3 years ago
5 0

Answer:

CH4 and CH3CH2CH2CH3

Explanation:

its right on edg

nirvana33 [79]3 years ago
4 0

Answer:

CH4 and CH3 CH2 CH2 CH3

Explanation:

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What is the threshold frequency ν0 of cesium?
Montano1993 [528]
 I think this is what you're after:

 Cs(g) → Cs^+ + e⁻ ΔHIP = 375.7 kJ mol^-1 [1] 


Convert to J and divide by the Avogadro Const to give E in J per photon 


E = 375700/6.022×10^23 = 6.239×10^-19 J 


Plank relationship E = h×ν E in J ν = frequency (Hz s-1) 


Planck constant h = 6.626×10^-34 J s 


6.239×10^-19 = (6.626×10^-34)ν 


ν = 9.42×10^14 s^-1 (Hz) 


IP are usually given in ev Cs 3.894 eV 


<span>E = 3.894×1.60×10^-19 = 6.230×10^-19 J per photon </span>

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3 years ago
Air pressure decreases more rapidly with altitude within a column of ________ air than in a column of __________ air.
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Air Pressure drops more rapidly with altitude in a column of cold air than in warm air.The answers to this question are cold air and warm air, respectively. 
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4 0
3 years ago
a sample of compound determined to contain 1.71 g C and 0.287 g H. The corresponding empirical formula is
fiasKO [112]

Answer: The empirical formula is CH_2.

Explanation:

Mass of C = 1.71 g

Mass of H = 0.287 g

Step 1 : convert given masses into moles.

Moles of C = \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{1.71g}{12g/mole}=0.142moles

Moles of H = \frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.287g}{1g/mole}=0.287moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =\frac{0.142}{0.142}=1

For H =\frac{0.287}{0.142}=2

The ratio of C: H = 1: 2

Hence the empirical formula is CH_2.

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Answer:

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The advantage of steam distillation over simple distillation is that the lower boiling point reduces decomposition of temperature -sensitive compounds.

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