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Shtirlitz [24]
3 years ago
11

I need the answer and the answers are there

Mathematics
1 answer:
sergeinik [125]3 years ago
5 0

Answer:

Step-by-step explanation:

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The school cafeteria sells apples for $0.25 and pears for $1.15. On Thursday
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D because they sold $1.50 for apples and 3.45 for pears add that up and it’ll be 4.95
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3 years ago
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Pluto's distance P(t)P(t)P, left parenthesis, t, right parenthesis (in billions of kilometers) from the sun as a function of tim
Xelga [282]

Answer: P(t) = 1.25.sin(\frac{\pi}{3}.t) + 5.65

Step-by-step explanation: A motion repeating itself in a fixed time period is a periodic motion and can be modeled by the functions:

y = A.sin(B.t - C) + D or y = Acos(B.t - C) + D

where:

A is amplitude A=|A|

B is related to the period by: T = \frac{2.\pi}{B}

C is the phase shift or horizontal shift: \frac{C}{B}

D is the vertical shift

In this question, the motion of Pluto is modeled by a sine function and doesn't have phase shift, C = 0.

<u>Amplitude</u>:

a = \frac{largest - smallest}{2}

At t=0, Pluto is the farthest from the sun, a distance 6.9 billions km away. At t=66, it is closest to the star, P(66) = 4.4 billions km. Then:

a = \frac{6.9-4.4}{2}

a = 1.25

<u>b</u>

A time period for Pluto is T=66 years:

66 = \frac{2.\pi}{b}

b = \frac{\pi}{33}

<u>Vertical</u> <u>Shift</u>

It can be calculated as:

d = \frac{largest+smallest}{2}

d = \frac{6.9+4.4}{2}

d = 5.65

Knowing a, b and d, substitute in the equivalent positions and find P(t).

P(t) = a.sin(b.t) + d

P(t) = 1.25.sin(\frac{\pi}{3}.t) + 5.65

The Pluto's distance from the sun as a function of time is

P(t) = 1.25.sin(\frac{\pi}{3}.t) + 5.65

8 0
3 years ago
SOMEONE PLZZZ HELP THIS IS DUE IN 2 MINSSS
nydimaria [60]

Answer:

D, and C sorry if I'm wrong

5 0
3 years ago
Find the area in cm2 of a rhombus whose side length is 29 cm and
kotegsom [21]
\left(\frac{d}{2}\right)^2+\left(\frac{d+2}{2}\right)^2=29^2\\\\\frac{d^2}{4}+\frac{d^2+4d+4}{4}=841\ \ \ \ /\cdot4\\\\d^2+d^2+4d+4=3364\\\\2d^2+4d+4-3364=0\\\\2d^2+4d-3360=0\ \ \ \ /:2\\\\d^2+2d-1680=0

a=1;\ b=2;\ c=-1680\\\\\Delta=b^2-4ac\to\Delta=2^2-4\cdot1\cdot(-1680)=4+6720=6724\\\\\sqrt\Delta=\sqrt{6724}=82\\\\d_1=\frac{-b-\sqrt\Delta}{2a}\to d_1=\frac{-2-82}{2\cdot1} < 0\\\\d_2=\frac{-b+\sqrt\Delta}{2a}\to d_2=\frac{-2+82}{2\cdot1}=\frac{80}{2}=40\ (cm)\\\\d=40cm;\ d+2=42cm\\\\A_r=\frac{d(d+2)}{2}\to A_r=\frac{40\cdot42}{2}=840\ (cm^2)

3 0
4 years ago
Similar Triangles
Fudgin [204]

Answer:

B. 3/9 = 4/12 = 1/3

Step-by-step explanation:

I calculated it logically

3 0
3 years ago
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