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4 years ago

Trigonometric identitie

Mathematics

1 answer:

erik [133]4 years ago

4 0

There are many forms, one of them is
sinθ cosθ - sin²θ

are there choices for this question?

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Help me out here pleaseeeeeee

Sveta_85 [38]

Answer:

(4, 80) Which is L

Step-by-step explanation:

First number should be on the X axis and the second on the Y axis.

6 0

3 years ago

Meg scored 45, 48, and 56 points on three tests. How many points should she get on the fourth test to get an average score of 60

Diano4ka-milaya [45]

Hey it’s 91 have a great day

4 0

3 years ago

Read 2 more answers

Use the Polynomial Identity below to help you create a list of 10 Pythagorean Triples:

Stolb23 [73]

Answer:

(3,4,5)

(6,8,10)

(5,12,13)

(8,15,17)

(12,16,20)

(7,24,25)

(10,24,26)

(20,21,29)

(16,30,34)

(9,40,41)

Just choose 2 numbers from {1,2,3,4,5,6,7,8,...} and make sure the one you input for x is larger.

Post the three in the comments and I will check them for you.

Step-by-step explanation:

We need to choose 2 positive integers for x and y where x>y.

Positive integers are {1,2,3,4,5,6,7,.....}.

I'm going to start with (x,y)=(2,1).

x=2 and y=1.

$(2^2+1^2)^2=(2^2-1^2)^2+(2\cdot2\cdot1)^2$

$(4+1)^2=(4-1)^2+(4)^2$

$(5)^2=(3)^2+(4)^2$

So one Pythagorean Triple is (3,4,5).

I'm going to choose (x,y)=(3,1).

x=3 and y=1.

$(3^2+1^2)^2=(3^2-1^2)^2+(2\cdot3\cdot1)^2$

$(9+1)^2=(9-1)^2+(6)^2$

$(10)^2=(8)^2+(6)^2$

So another Pythagorean Triple is (6,8,10).

I'm going to choose (x,y)=(3,2).

x=3 and y=2.

$(3^2+2^2)^2=(3^2-2^2)^2+(2\cdot3\cdot2)^2$

$(9+4)^2=(9-4)^2+(12)^2$

$(13)^2=(5)^2+(12)^2$

So another is (5,12,13).

I'm going to choose (x,y)=(4,1).

$(4^2+1^2)^2=(4^2-1^2)^2+(2\cdot4\cdot1)^2$

$(16+1)^2=(16-1)^2+(8)^2$

$(17)^2=(15)^2+(8)^2$

Another is (8,15,17).

I'm going to choose (x,y)=(4,2).

$(4^2+2^2)^2=(4^2-2^2)^2+(2\cdot4\cdot2)^2$

$(16+4)^2=(16-4)^2+(16)^2$

$(20)^2=(12)^2+(16)^2$

We have another which is (12,16,20).

I'm going to choose (x,y)=(4,3).

$(4^2+3^2)^2=(4^2-3^2)^2+(2\cdot4\cdot3)^2$

$(16+9)^2=(16-9)^2+(24)^2$

$(25)^2=(7)^2+(24)^2$

We have another is (7,24,25).

You are just choosing numbers from the positive integer set {1,2,3,4,... } and making sure the number you plug in for x is higher than the number for y.

I will do one more.

Let's choose (x,y)=(5,1).

$(5^2+1^2)^2=(5^2-1^2)^2+(2\cdot5\cdot1)^2$

$(25+1)^2=(25-1)^2+(10)^2$

$(26)^2=(24)^2+(10)^2$

So (10,24,26) is another.

Let (x,y)=(5,2).

$(5^2+2^2)^2=(5^2-2^2)^2+(2\cdot5\cdot2)^2$

$(25+4)^2=(25-4)^2+(20)^2$

$(29)^2=(21)^2+(20)^2$

So another Pythagorean Triple is (20,21,29).

Choose (x,y)=(5,3).

$(5^2+3^2)^2=(5^2-3^2)^2+(2\cdot5\cdot3)^2$

$(25+9)^2=(25-9)^2+(30)^2$

$(34)^2=(16)^2+(30)^2$

Another Pythagorean Triple is (16,30,34).

Let (x,y)=(5,4)

$(5^2+4^2)^2=(5^2-4^2)^2+(2\cdot5\cdot4)^2$

$(25+16)^2=(25-16)^2+(40)^2$

$(41)^2=(9)^2+(40)^2$

Another is (9,40,41).

5 0

3 years ago

Reflection over the y-axis followed by a horizontal translation 1 unit left on the equation f(x)=x

aleksley [76]

Answer:

f(x) = -x -4 or f(x) = (-x)-4

Step-by-step explanation:

Let the graph of g be a translation of 4 units down followed by a reflection in the y-axis of the graph of f(x)=x. Write a rule for g.

Transformations can be found using this general formula: f(x) = a(bx-h)+k

For this question, we want a translation down as well as a reflection.

The two values we need to use are for k, a vertical translation, and b, a reflection over the y-axis.

Since we are translating down 4 units, k = -4

Since we are reflecting across the y-axis, b = -1

So, f(x)=(-x)-4

f(x)= -x -4

6 0

3 years ago

What is the solution to: <br> T/t-4=t+4/6

S_A_V [24]

$\frac{t}{t-4}= \frac{t+4}{6} \\ t \neq 4 \\ 6t= (t+4)(t-4) \\ 6t=t^2-16 \\ t^2-6t-16=0 \\ D=b^2-4ac=(-6)^2-4*1*(-16)=36+64=100 \\ t_{1,2}= \frac{-bб \sqrt{D} }{2a} \\ t_1= \frac{6-10}{2}=-2 \\ \ t_2= \frac{6+10}{2}=8$

Answer: t=-2, t=8

4 0

3 years ago

Trigonometric identitie​

Trigonometric identitie