The figure below is a net for a triangular prism. Side a = 22 feet, side b = 14 feet, side c = 13 feet, side d = 13 feet, and si
de e = 19 feet. What is the surface area of this figure?
A. 1,194 square feet
B. 908 square feet
C. 1,172 square feet
D. 1,216 square feet
1 answer:
Answer:
the answer is 1,194
Step-by-step explanation:
what you want to do is find the area of 2 triangles and 3 rectangles
area of 1st rectangle
1 = ae
=(22 ft) (19 ft)
=418 sq. ft.
area of 2nd rectangle
2 = ab
=(22 ft.) (14 ft.)
=308 sq. ft.
area of 3rd rectangle
3=ad
=(22 ft.) (13 ft.)
=286 sq. ft.
area of 1st triangle
Area of triangle = 1/2 cb
=1/2 (13ft) (14ft)
= 1/2 (182 sq. ft)
=91 sq. ft.
***this would be the same for 2nd triangle*** 91 sq ft.
Next add all areas together to get the total surface area
Total surface area = ae + ab + ad + 2 (1/2 cb)
= 418 sq. ft + 308 sq. ft. + 286 sq. ft. + 2(91 sq. ft)
=418 + 308 + 286 + 182
= 1,194 sq. ft.
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