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Elina [12.6K]
3 years ago
10

How long will it take for 2 g of a sample of iodine-131, which has a half-life of about 8 days, to decay to 0.04 g?

Mathematics
1 answer:
Zigmanuir [339]3 years ago
6 0
We know that

<span>This problem can be represented through the following equation
</span>
A = A₀(1/2)^t/h
where
A----------->  is the amount of substance left after time t
A₀ ----------> is the original amount---------> 2 g
h------------->  is the half-life-----------> 8 days

for A=0.04 g
t=?
0.04 = 2(1/2)^t/8
0.02 = (1/2)^t/8
Take ln on both sides:
ln(0.02) = ln [(1/2)^t/8]
ln(0.02) = (t/8)(ln 1/2)
t = 8*ln(0.02)/ln(1/2)
t = 45.15 days

the answer is 45.15 days
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NEED HELP ASAP!!!!!!!!!!!!
Mice21 [21]

Answer:

p(0) = 800

p(8) = 997

Step-by-step explanation:

p(t) = 800 * (1.028)^t

The current price is when t=0

p(0) = 800 * (1.028)^0

       = 800(1)

       = 800

The price in 8 years

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       =997.7802522414861936754688

To the nearest dollar

        = 998

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