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3 years ago

10

Which statement about the sides is true?

2 answers:

Vinvika [58]3 years ago

6 0

Step-by-step explanation:

i guess the answer is the last one

Nataliya [291]3 years ago

3 0

Answer:

the correct answer is the one

Step-by-step explanation:

I have got all correct answers

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What does |x| mean in a function?

seropon [69]

Answer:

<h2><u><em>The function basically returns the same objects (= does nothing). This could also be written explicitly as a named function. new Function <- function(x) { x } which would then be. cross val <- function(data, lambda=0, y trans = new Function) This is the default value, like in lambda=0, except the default value is a function itself.</em></u></h2><h2><u>brainlist plz </u></h2>

Step-by-step explanation:

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4 years ago

Which expressions are equivalent to -3(2+7) A: -6+21 or B:-21+6

Neporo4naja [7]

<u>Answer:</u>

None

<u>Explanation:</u>

-3(2+7) = -3×9 = -27

-6+21 = 15

-21+6 = -15

Hence there is no equivalence

3 0

3 years ago

SOMEBODY PLEASE HELP!! (view picture, math related$

Flauer [41]

Answer:

the answer is B

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The graph of a line passes through the points (0, -2) and (6.0). What is

9966 [12]

Answer:

$y=\frac{1}{3}x-2$

Step-by-step explanation:

The equation of a line is given in the form $y=mx+b$

Where

m is the slope with formula $m=\frac{y_2-y_1}{x_2-x_1}$

and

b is the y-intercept [y axis cutting point of line]

Given the two points (0, -2) and (6,0),

x_1 = 0

y_1 = -2

x_2 = 6

y_2 = 0

Now, we find m using formula:

$m=\frac{0+2}{6-0}=\frac{1}{3}$

Now we have

$y=\frac{1}{3}x+b$

Finding b, we plug in any (x,y) point. Lets put (6,0) and find b:

$y=\frac{1}{3}x+b\\0=\frac{1}{3}(6)+b\\0=2+b\\b=-2$

Thus,

equation of line = $y=\frac{1}{3}x-2$

5 0

3 years ago

Please help me solve this ;-;

Digiron [165]

9514 1404 393

Answer:

C log3(√((x -4)/x)

Step-by-step explanation:

The applicable rules of logarithms are ...

log(a/b) = log(a) -log(b)

log(a^n) = n·log(a)

The base is irrelevant, as long as all logs are to the same base.

__

$\dfrac{1}{2}(\log_3{(x-4)}-\log_3{(x)})=\dfrac{1}{2}\log_3(\dfrac{x-4}{x})=\boxed{\log_3\left(\sqrt{\dfrac{x-4}{x}}\right)}$

6 0

3 years ago