Answer:
a) 
b) 0.2046 = 20.46% probability the driving distance for one of these golfers is less than 290 yards
Step-by-step explanation:
Uniform probability distribution:
An uniform distribution has two bounds, a and b.
The probability of finding a value of at lower than x is:

The probability of finding a value between c and d is:

The probability of finding a value above x is:

The probability density function of the uniform distribution is:

The driving distance for the top 100 golfers on the PGA tour is between 284.7 and 310.6 yards.
This means that
.
a. Give a mathematical expression for the probability density function of driving distance.

b. What is the probability the driving distance for one of these golfers is less than 290 yards?

0.2046 = 20.46% probability the driving distance for one of these golfers is less than 290 yards
Answer: Cylinder 1 - 25.1327412283 cubic cm
Cylinder 2 - 100.5309469149 cubic cm
Cylinder 3 - 226.1946710585 cubic cm
For each of the cylinders, we will need to use the same formula, h(pi(r squared)).
Cylinder 1 - 8(pi(1 squared)). 1 squared = 1. pi × 1 = 3.1415926536. 3.1415926536 × 8 = 25.1327412283 cubic cm.
Cylinder 2 - 8(pi(2 squared)). 2 squared = 4. 4 × pi = 12.5663706144. 12.5663706144 × 8 = 100.5309469149 cubic cm.
Cylinder 3 - 8(pi(3 squared)). 3 squared = 9. 9 × pi = 28.2743338823. 28.2743338823 × 8 = 226.1946710585 cubic cm.
- Hope it helps!
Answer:
(25)-(3)
Step-by-step explanation:
Answer:

Step-by-step explanation:
As per the problem, the given triangle is a right triangle. This is signified by the box around one of its angles, this box states that the angle it is surrounding is a right angle.
Since it is a right triangle, one can use the Pythagorean theorem to solve this problem. The Pythagorean theorem states that; (
), where (
) and (
) are the legs of the right triangle, or the sides adjacent to the right angle. (
) is the hypotenuse or the side opposite the right angle.
Substitute in the given values and solve, note that (
) represents the unknown leg (side).

Inverse operations,
