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3 years ago

If c=8, what is the value of 4c+(4-3)

Mathematics

2 answers:

zloy xaker [14]3 years ago

5 0

Answer:

$33$

Step-by-step explanation:

$c = 8$

Substitute 8 in the equation where c is.

$4(8) + 4 - 3 \\ 32 + 1 \\ = 33$

kvv77 [185]3 years ago

3 0

The answer is 33

Explanation
4c+(4-3)
C=8
Substitution
4x8+4-3
Calculate
4x8+4-3
32+4-3
Which equal 33 that’s how I got the answer

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The manufacturer of computers spends $500 to make each computer and sells them for 800. The manufacturer also has fixed costs ea

ryzh [129]

Answer:

C(x) = 5700 + 500x

Step-by-step explanation:

Total cost = fixed cost + variable cost

Fixed cost are cost that do not change in the process of production such as machineries, furnitures & fittings.

Variable cost are cost that changes with production such as cost of raw material, cost of labor.

From the question:

Fixed cost= $5,700

Cost per unit of computer = $500

If x number of computers are produced in a month

Variable cost = 500x

Total cost = fixed cost + variable cost

C(x) = 5700 + 500x

Where,

C(x) = total cost

5700= fixed cost

500x= variable cost

3 0

4 years ago

Read 2 more answers

A book claims that more hockey players are born in January through March than in October through December. The following data sh

astra-53 [7]

Answer:

$\chi^2 = \frac{(67-47.5)^2}{47.5}+\frac{(56-47.5)^2}{47.5}+\frac{(30-47.5)^2}{47.5}+\frac{(37-47.5)^2}{47.5}=18.295$

Now we can calculate the degrees of freedom for the statistic given by:

$df=(categories-1)=4-1=3$

And we can calculate the p value given by:

$p_v = P(\chi^2_{3} >18.295)=0.00038$

Since the p value is very low we have enough evidence to reject the null hypothesis and we can conclude that the players' birthdates are not uniformly distributed throughout the year

Step-by-step explanation:

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is no difference of birthdates distributed throughout the year

H1: There is a difference between birthdates distributed throughout the year

The level of significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{total}{4}$

And replacing we got:

$E_{1} =\frac{67+56+30+37}{4}=47.5$

And now we can calculate the statistic:

$\chi^2 = \frac{(67-47.5)^2}{47.5}+\frac{(56-47.5)^2}{47.5}+\frac{(30-47.5)^2}{47.5}+\frac{(37-47.5)^2}{47.5}=18.295$

Now we can calculate the degrees of freedom for the statistic given by:

$df=(categories-1)=4-1=3$

And we can calculate the p value given by:

$p_v = P(\chi^2_{3} >18.295)=0.00038$

Since the p value is very low we have enough evidence to reject the null hypothesis and we can conclude that the players' birthdates are not uniformly distributed throughout the year

3 0

4 years ago

Center (8,9) and radius r=10

LekaFEV [45]

Answer:

A. Standard form: $(x-8)^2+(y-9)^2=100$