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zhannawk [14.2K]
3 years ago
5

What is the value of y?

Mathematics
2 answers:
Korolek [52]3 years ago
7 0

Answer:

A. 55

Step-by-step explanation:

55 + 30 + 40 + 55 = 180

I hope this helps u! :D

Makovka662 [10]3 years ago
7 0

Answer:

The answer is option A.

<h2>55°</h2>

Step-by-step explanation:

Angles in a triangle add up to 180°

To find y add up all the angles and equate them to 180°

That's

y + 40 + y + 30 = 180

2y = 180 - 70

2y = 110

Divide both sides by 2

<h3>y = 55°</h3>

Hope this helps you

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If a positive integer is equal to the following product: 25b3c425b3c4, where b and c are distinct prime numbers greater than 2,
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Answer: 64 distinct even factors

Step-by-step explanation:

let the 2 distinct numbers be b and c and the integer is expected to be 25b3c425b3c4

since b, c > 2 and prime numbers,

potential options include 3, 5, and 7

hence the likelihoods are (b = 3, c = 5), (b = 5, c = 3), (b = 3, c = 7), (b = 7, c = 3), (b = 5, c = 7), (b = 7, c = 5)

Possibility 1 (b = 3, c = 5)

integer is now 253354253354

the distinct even factors = 2, 202, 262, 1934, 19802, 26462, 195334, 253354, 2000002, 2594062, 19148534, 25588754, 262000262, 1934001934, 2508457954, 253354253354

number of distinct even factors = 16

Possibility 2 (b = 5, c = 3)

integer is now 255334255334

the distinct even factors = 2, 86, 202, 5938, 8686, 19802, 253354, 599738, 851486, 2000002, 25788734, 58792138, 25588754, 86000086, 2528061934, 1934001934, 5938005938, 253354253354

number of distinct even factors = 18

Possibility 3 (b = 3, c = 7)

integer is now 253374253374

the distinct even factors = 2, 6, 22, 66, 202, 242, 606, 698, 726, 2094, 2222, 6666, 7678, 19802, 23034, 24442, 59406, 70498, 73326, 84458, 211494, 217822, 253374, 653466, 775478, 2000002, 2326434, 2396042, 6000006, 6910898, 7188126, 8530258, 20732694, 22000022, 25590774, 66000066, 76019878, 228059634, 242000242, 698000698, 726000726, 836218658, 2094002094, 2508655974, 7678007678, 23034023034, 84458084458,253354253354

number of distinct even factors = 48

Possibility 4 (b = 7, c = 3)

integer is now 257334257334

the distinct even factors = 2, 6, 14, 22, 42, 66, 154, 202, 462, 606, 1114, 1414, 2222, 3342, 4242, 6666, 7798, 12254, 15554, 19802, 23394, 36762, 46662, 59406, 85778, 112514, 138614, 217822, 257334, 337542, 415842, 653466, 787598, 1237654, 1524754, 2000002, 2362794, 3712962, 4574262, 6000006, 8663578, 11029714, 14000014, 22000022, 25990734, 33089142, 42000042, 66000066, 77207998, 121326854, 154000154, 231623994, 363980562, 462000462, 849287978, 1114001114, 2547863934, 3342003342, 7798007798, 12254012254, 23394023394, 36762036762, 85778085778, 257334257334

number of distinct even factors = 64

Possibility 5 (b = 5, c = 7)

integer is now 255374255374

the distinct even factors = 2, 14, 34, 58, 74, 202, 238, 406, 518, 986, 1258, 1414, 2146, 3434, 5858, 6902, 7474, 8806, 15022, 19802, 24038, 36482, 41006, 52318, 99586, 127058, 138614, 216746, 255374, 336634, 574258, 697102, 732674, 889406, 1517222, 2000002, 2356438, 3684682, 4019806, 5128718, 9762386, 12455458, 14000014, 21247546, 25792774, 34000034, 58000058, 68336702, 74000074, 87188206, 148732822, 238000238, 361208282, 406000406, 518000518, 986000986, 1258001258, 2146002146, 2528457974, 6902006902, 8806008806, 15022015022, 36482036482, 255374255374

number of distinct even factors = 64

Possibility 6 (b = 7, c = 5)

integer is now 257354257354

the distinct even factors = 2, 202, 19802, 257354, 2000002, 25992754, 2548061954, 257354257354

number of distinct even factors = 8

From the six possibilities, the highest number of likely distinct even factors is 64

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if the mean of a population is 250 and its standard de- viation is 20, approximately what proportion of obser- vations is in the
Anton [14]

Observed proportions (relative frequencies) from a sample are statistics that can be used to estimate probabilities.

a) Thre is 99.73% proportion of observations is in between 190 and 310 .

b)there is 95.44% proportion of observations is in between 210 and 290 .

We have given that,

Mean of population, μ = 250

standard deviations, σ = 20

we have to calculate proportion of observations in the given interval pair.

a) pair of values are 190 and 310

Using Z-score formula,

Z =( x - μ) /σ

=> Z = (190 - 250) / 20 = -3

Similarly, Z = (310 - 250)/20 = 3

So, -3 < z < 3 and from Z score we found p-value

P(190<X<310) = P( 190-u/sd < X-u/sd < 310-u/sd)

= P( X< 310 ) - P(X<190) = P(Z < 3) - P( Z< -3 )

=0.99865 - 0.00135 0.9973 = 99.73%

b) pair is 210 and 290

Z-Score = (210-250)/20 = -2

Z-score = (290-250)/20 = 2

so, -2 < z < 2

From Z score we found p-value

P(210<X<290) = P(X<290) - P(X<210)

= P(Z< 2) - P(Z< -2)

= 0.9772 - 0.0228 = 0.9544 = 95.44%

So, the required proportion are 99.73% and 95.44% proportion of observations in each given pair.

To learn more about Proportion value , refer:

brainly.com/question/19131394

#SPJ4

Complete question:

If the mean of a population is 250 and its standard deviation is 20, approximately what proportion of observations is in the interval between each pair of values? a 190 and 310 b. 210 and 290.

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1 year ago
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