Please help!!!!! Please explain too, I want to understand it!
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Answer:
a)
<em> you are unwilling to predict the proportion value at your school = 0.90</em>
<em>b) </em>
<em>The large sample size 'n' = 864</em>
<em></em>
Step-by-step explanation:
Given estimated proportion 'p' = 10% = 0.10
<em>Given Margin of error M.E = 0.02</em>
<em>Level of significance α = 0.05</em>
a)
<em> you are unwilling to predict the proportion value at your school </em>
<em> q = 1- p = 1- 0.10 =0.90</em>
b)
<em>The Margin of error is determined by</em>
Cross multiplication , we get
√n = 29.4
<em>Squaring on both sides , we get</em>
<em> n = 864.36</em>
<u><em>Conclusion</em></u><em>:-</em>
<em>The large sample size 'n' = 864</em>
<em></em>
<em></em>