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zaharov [31]
3 years ago
7

What is the factored form of this expression? x2 − 121 HELP!!!!

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
6 0

Answer:x= -11 or x= 11

Step-by-step explanation:tell me if you need more explaining

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A train travels 220 miles in 4 hours. What is the train's speed in feet per minute?
Katena32 [7]
220 miles in 4 h = 55 mph multiply this by 5280 to get feet per hour then divide this by 60 to get ft/min


7 0
4 years ago
Read 2 more answers
We want to find the zeros of this polynomial:
fredd [130]

Answer:

x = -3 and x = -3/2

Step-by-step explanation:

After writing down the polynomial, split it; put a line between 3x^2 and -18x. Look and 2x^3 + 3x^2 and -18x - 27 separately and factor them both:

p(x) = 2x^3 + 3x^2 <u>- 18x -27</u>

p(x) = x^2(2x+3) <u>-9(2x+3)</u>

Now notice how x^2 and -9 have the same factor (2x+3). That means x^2 and -9 can go together:

p(x) = (x^2 - 9)(2x+3)

Factor it once more because there's a difference of squares:

p(x) = (x+3)(x-3)(2x+3)

Now just plug in whatever makes the each bracket equal 0:

x = -3, x = 3, and x = -3/2

Those are your zeros.

8 0
3 years ago
HELPPP ME PLEASE WILL MARK BRAINLIEST IF YOU GIVE ME THE CORRECT ANSWER
Salsk061 [2.6K]

Answer:

Option (3)

Step-by-step explanation:

Properties for the vertical stretch or shrink of a function,

If a function is f(x) = k|x|

1). Function will be vertically stretched if k > 1

2). Function will have a vertical shrink if 0 < k < 1

To fit the given data graph of f(x) = |x| will vertically shrink without any translation along x or y-axis.

And the value of k will be, 0 < k < 1.

Therefore, g(x) = \frac{1}{3}f(x) will be the transformed graph.

Therefore, Option (3) will be the correct option.

6 0
3 years ago
Can any one help me with these questions
qwelly [4]
35divide by 3 and your answer


3 0
3 years ago
Which equation represents y = −x^2 − 10x − 20 in vertex form?
olchik [2.2K]
The vertex is (-5, 5) and the parabola opens downward. The vertex form equation is
.. y = -(x +5)^2 +5

4 0
4 years ago
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