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Aloiza [94]
3 years ago
12

At a school fair, each student spins the spinner, which is equally likely to land on each of the four sectors. The spinner shows

how many tokens the student wins or loses. What is the expected number of tokens that a student will win on each spin

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
3 0

Answer:

3 tokens.

Step-by-step explanation:

We need the roulette image, therefore we will suppose one that I will leave as an attached image:

The main thing to keep in mind in this case is that the probabilities are the same, therefore you don't have to take that into account, just operate with the values of each sector, therefore the expected value would be:

expected value = profit - loss

expected value = (5 + 5) - (4 + 3)

expected value = 10 - 7 = 3

This means that the number of tokens waiting for the student to earn for each spin is 3 tokens.

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EXPLAIN IT WORD FOR WORD ON HOW TO SOLVE IT
eimsori [14]
To start, first add up the total number of reservations made this week which would be adding up the total amount of reservations for each day:
15+5+10+25+40+30+35= 160
Then, since it is asking for the percent of Friday and Saturday, add the amounts together (40+30) which is 70. 
Then, set these as a fraction where it is the reservations for Friday and Saturday over the total amount of reservations: 70/160
Now that you got that, do 70 divided by 160 which is 0.4375.
Finally, convert 0.4375 to a percent by moving the decimal right two and you get 43.75% as your answer.

5 0
3 years ago
Please help! I will mark as brainliest IF answer is right. <3
Alex17521 [72]

\large\underline{\rm Solution }:-

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\underline\text{ In Interval Notation :- }

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6 0
3 years ago
Using Special Angle Triangles find the exact value :
Nikitich [7]

Answer:

Step-by-step explanation:

Trigonometric  table has the value of the trigonometric ratio of Sin, Cos ,  Tan , Csc, Sec & Cot of the angles 0° , 30°, 45° , 60°, 90°

Cos 45 = \frac{1}{\sqrt{2} }

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Csc 45 = \sqrt{2}\\\\\\Sec 60 = 2

6 0
3 years ago
A mosquito is walking at random on the nonnegative number line. She starts at $1$. When she is at $0$, she always takes a step $
nikitadnepr [17]

Answer:

The expected number of times is 4.

Step-by-step explanation:

Looking at the question, we see that this follows a geometric distribution because it is asking for the expected number of trials hat will bring about the FIRST SUCCESS. The probability of success is

\frac{1}{4}

Since it is a geometric distribution, we know that the expected value of a random variable X, E(X) that follows a geometric distribution is given as:

E(X) = 1/p where p is the probability of success.

Therefore, the expected number of times will be

E(X) = 1/(1/p) = 1/(1/4) = 4.

Hence, the expected number of times is 4.

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