Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60

t=1
It's sometimes true.
One example is the least common multiple of 2 and 3 is 6, which is their product.
But the product isn't always the answer because (example 2:) the least common multiple of 6 and 10 is 30 because 6*5=30 and 3*10=30, however 6*10 is 60.
Ergo, it is only sometimes true.
Answer:
24 = x
Step-by-step explanation:
You use Pythagorean theorem. Since the normal equation is
, you already have the
and another side which can be
or
.
Because you have the hypotenuse and a side , your equation looks like this now:
and when you solve for be you just subtract
to get 24.
Answer:
Step-by-step explanation:
slope m= (y2-y1) / (x2-x1) = 15-12 / 4-4 = 3/0 is undefined since we can not divide by 0
slope is undefined so the line is vertical