Answer:
61
Step-by-step explanation:
99 minus 38
Let x and y be your two consecutive whole numbers
x < sqrt(142) < y
x^2 < 142 < y
So, we are looking for x and y such that x^2 < 142 and y^2 > 142.
The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.
11 and 12 are consecutive.
11^2 = 121 < 142 < 144 = 12^2
Thus, 11 and 12 are your numbers
165
5x5= 25
12x12=144
25+144= 165
Answer:
Step-by-step explanation:
add a picture of the question please
Answer:
-3
Step-by-step explanation:
f(x) = x2 – 4
replace x with -1
f(-1) = (-1)^2 – 4
= -3