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alexira [117]
4 years ago
15

In the figure, ∆ABD ≅ ∆CBD by Angle-Side-Angle (ASA). Which segments are congruent by CPCTC?

Mathematics
2 answers:
k0ka [10]4 years ago
8 0

Answer: AB ≅ CB

Step-by-step explanation:

In the given figure, we have ∆ABD ≅ ∆CBD

The CPCTC property of congruent triangles says that if two triangles are congruent then their corresponding parts ( angles and segments ) are congruent.

Since we have given that ∆ABD ≅ ∆CBD.

Therefore, the corresponding segments are congruent.

As segment AB is corresponding to segment CB. [First two letters]

Therefore, segment AB is congruent to segment CB.

3241004551 [841]4 years ago
5 0
AB = BC l guess this is the answer
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Can somebody please help me, this is due in 20 minutes​
Alex73 [517]

Answer:

61°

Step-by-step explanation:

In order for triangle LMN and PQR to be congruent, angle M and angle Q must equal. thus, we can set 2x-26=x+16

with basic algebraic manipulation, x=42. we then plug it back into the angle M or Q, getting angle M/Q= 58°

since this is a isoceles, the 2 base angle are identical, so 180= 58+2(angle P)

thus, angle P= 61

6 0
3 years ago
877+100=__+258help me​
Arada [10]

Answer:

719 = x

Step-by-step explanation:

877+100=_x_+258

Combine like terms

977 = x+258

Subtract 258

977 -258 = x+258-258

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8 0
3 years ago
Read 2 more answers
Is 7m + 6 - 5 = 15 equivalent to 2m +5 =9
aliya0001 [1]

Answer:yes

Step-by-step explanation:

You have to simplify each equation

7m +6 - 5 = 15 2m + 5 = 9

7m + 1 = 15 2m = 4

7m = 14 m = 2

M = 2

They both end up with the same answer so they are equivalent

4 0
3 years ago
Prove that if n or m is an odd integer, then n*m is an even integer. Proposed proof: Suppose that n*m is odd. Then n*m = 2k + 1
Irina-Kira [14]

Answer: Ok, we have two numbers, and one of them is an odd integer, and the other is even.

Lets call M to the odd integer and N the even.

We know that a even integer can be written as 2k, where k is a random integer, and a odd integer can be written as 2j + 1, where j is also a random integer.

then M = 2k, N= 2j+1

then the product of M and N is: M*N = 2*k*(2*j + 1) = 2*(k*2*j + k)

is obvious to see that (k*2*J + k) is a integer, because k and j are integers.

then if we call g = ( k*2*J + k), we can write M*N=2g, and we already know that this is an even number. So M*N is a even integer.

4 0
3 years ago
The grades in period 3 algebra 2 have an average of 82 nd vary by 12 percentage points. formulate an absolute value equation tha
Sergeu [11.5K]

The absolute value equation used to solve this problem: | x - 82 | = 12, where x = grade.

<h3>What is an absolute value equation?</h3>
  • A statement that contains an absolute value is known as an absolute value equation.
  • The absolute value contains the variable of the equation.

Now,

Given:

  • The average of grades = 82%
  • Variation = 12%

Let 'x' be the value that gives the value of grades.

The absolute value equation to find the grades will be given by: | x - 82 | = 12

=> x - 82 = ± 12

For maximum value of the grades, x - 82 = 12

=> x = 82 + 12

=> x = 94.

For minimum value of the grades, x - 82 = -12

=> x = 82 - 12

=> x = 70.

Hence, The absolute value equation used to solve this problem: | x - 82 | = 12, where x = grade.

To learn more about absolute value equation, refer to the link: brainly.com/question/5012769

#SPJ4

5 0
1 year ago
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