Compute the work preformed when 32 pounds is lifted 10 feet_____________WHOEVER GIVES RIGHT ANSWER GETS BRAINLEST
1 answer:
Given that work is the vectorial product of displacement and force. Work can be found with the formula W=F·d
The force that does work as the weight is lifted is gravity. The force is weight
Hence
F
=F
= weight
= mass(acceleration due to gravity)
= 32 pounds(9.8 m/s²)
=14.51(9.8) N
= 142.198
With the F= 142.2, d=10 ft = 3.04 m
W=F·d
= 142.2· 3.04
= 432.228 J (Joules)
432.228 joules of work was done
The force that does work as the weight is lifted is gravity. The force is weight
Hence
F
=F
= weight
= mass(acceleration due to gravity)
= 32 pounds(9.8 m/s²)
=14.51(9.8) N
= 142.198
With the F= 142.2, d=10 ft = 3.04 m
W=F·d
= 142.2· 3.04
= 432.228 J (Joules)
432.228 joules of work was done
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Answer:
Option A is correct.
y = 35.4 bushels per acre when rainfall = 7.1 inches
Step-by-step explanation:
An image of the steps to obtain the equation that relates x to y is attached to this answer.
n = number of variables = 9
μₓ = mean of variable x (rainfall in inches)
μᵧ = mean of variable y (yield in bushels per acre)
σₓ = standard deviation of variable x (rainfall in inches)
σᵧ = standard deviation of variable y (yield in bushels per acre)
y = 4.379x + 4.268
when x = 7.1
y = 4.379(7.1) + 4.268 = 35.3589 = 35.4 bushels per acre.
