All categories

3 years ago

9

Mathematics

1 answer:

vagabundo [1.1K]3 years ago

4 0

Answer:

u can use desmos

Step-by-step explanation:

You might be interested in

Problème mathématique:

Zanzabum

Answer:

yxughxc99uc0uf0ufohrulrrhlylfoy

5 0

3 years ago

Literal equations are equations containing

Maksim231197 [3]

Answer:

Literal equations, simply put, are equations containing two or more variables. Your goal is to solve for just one variable with respect to others

8 0

4 years ago

Read 2 more answers

12 +3/2s - 1/2 - 3/4s = 5/4s<br><br> How to solve for s?

rodikova [14]

s=1/23

given equation in term of s is 12+3/2s-1/2-3/4s=5/4s

to solve this first we need to take LCM on left hand side and right hand side we can rewrite given equation as 12/1+3/2s-1/2-3/4s=5/4s now taking LCM of {1,2s,2,4s,4s} is 4s then the equation becomes 48s/4s+6/4s-2s/4s-3/4s=5/4s

(48s+6-2s-3) /4s=5/4s now cancel out denominator of both side we get 48s+6-2s-3=5 this implies 46s+3=5

46s=2

s=1/23

Hence the value of s is 1/23

learn more about LCM here brainly.com/question/8463488

#SPJ9

3 0

1 year ago

Consider the functions f(x) = 2x and g(x) = <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx-3%7D" id="TexFormula1" title="\

bagirrra123 [75]

Question 1:

For this case we must find $(f_ {0} g) (4)$ knowing that:

$f (x) = 2x\\g (x) = \frac {1} {x-3}$

By definition we have that, be two functions f (x) and g (x), then the composite function of f with g is:

$(g_ {0} f) (x) = g [f (x)]$

In this case, they ask us for the function composed of g with f:

$(f_ {0} g) (x) = f [g (x)]$

So, we have:

$(f_ {0} g) (x) = 2 (\frac {1} {x-3})\\(f_ {0} g) (4) = 2 (\frac {1} {4-3})\\(f_ {0} g) (4) = 1$

ANswer:

$(f_ {0} g) (4) = 1$

Question 2:

For this case, we must find the inverse function of $g (x) = \frac {1} {x-3}$ , given by: $g ^ {- 1} (x)$

To do this, replace g(x) with y:

$y = \frac {1} {x-3}$

We exchange variables:

$x = \frac {1} {y-3}$

We solve for "y":

$y-3 = \frac {1} {x}\\y = \frac {1} {x} +3$

Replace "y" with $g ^ {-1} (x)$

So, we have:

$g ^ {- 1} (x) = \frac {1} {x} +3$

Answer:

$g ^ {- 1} (x) = \frac {1} {x} +3$

Question 3:

For this case, we have by definition, the domain of a function f (x), is the set of all the values for which the function is defined.

We must find the domain of the following function:

$g ^ {- 1} (x) = \frac {1} {x} +3$

It is observed that the function is not defined for $x = 0$

Then the domain is given by all the values of x, except 0.

${x | x \neq 0}$ for any integer n

Answer:

All numbers, except $x = 0$

4 0

3 years ago

Read 2 more answers

Can some one help me understand this???

lesya [120]

Answer: x=40 y=140

Step-by-step explanation:

To work out x:

The angles in a triangle always add up to 180.

You already have one angle which is 50 the bottom left angle is a right angle and right angles always equal 90. To work out x, do 50+90=140 then do 180-140=40.

To work out y:

Angles on a straight also add up to 180.

So as you have figured out what x is (40) you would take it away from 180 to give you y.

180-40=140

Hope this helps :)

8 0

3 years ago