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2 years ago

Please help. Click to view picture. Algebra question. HELP ME PLEASE ASAP

Mathematics

1 answer:

faltersainse [42]2 years ago

5 0

First you know you'll divide by -2, so the sign will be flipped.
That eliminates the first and second options, then you'll just have to do math.

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Help please! 6x^2+2x-9=0 A 6.4, -8.4 B 1.1, -1.4 C -2.2, 2.8 D -1.1, -1.4

Yakvenalex [24]

$6x^2+2x-9=0\\\\a=6;\ b=2;\ c=-9\\\\\Delta=b^2-4ac\to\Delta=2^2-4\cdot6\cdot(-9)=220\\\\x_1=\dfrac{-b-\sqrt\Delta}{2a};\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\x_1=\dfrac{-2-\sqrt{220}}{2\cdot6}=\dfrac{-2-\sqrt{220}}{12}\approx-1.4\\\\x_2=\dfrac{-2+\sqrt{220}}{2\cdot6}=\dfrac{-2+\sqrt{220}}{12}\approx1.1$

Answer: B. 1.1; -1.4.

6 0

3 years ago

Aaron is making jam using strawberries and raspberries. He made 1/2 a jar of strawberry jam. If he made 1/3 as much raspberry ja

nataly862011 [7]

Answer:

2/6 more.

Step-by-step explanation:

You need to find a common denominator. In this case it was 6.

5 0

2 years ago

Read 2 more answers

I NEED HELP PLEASE !!!!! :(

zubka84 [21]

Step-by-step explanation: use a histograph

4 0

3 years ago

The rate of U.S. per capita sales of bottled water for the period 2007–2014 could be approximated by s(t) = 0.25t2 ? t + 29 gall

julsineya [31]

Answer:

117 gallons

Step-by-step explanation:

The expression that describes the rate of U.S. per capita sales of bottled water for the period 2007–2014 is:

$s(t) = 0.25t^2-t+29$

Since t=0 at 2007. At 2009 and 2013, t is:

$t_1=2009-2007 = 2\\t_2=2013-2007 = 6$

The definite integral of the expression from t=2 to t=6 is:

$s(t) = 0.25t^2-t+29\\\int\limits^6_2 {s(t)} \, dt= \int\limits^6_2 {(0.25t^2-t+29)} \, dt\\\int\limits^6_2 {s(t)} \,dt= (\frac{t^3}{12} -\frac{t^2}{2}+29t +c)|^6_2 \\S(6) -S(2) = (\frac{6^3}{12} -\frac{6^2}{2}+29*6 +c) - (\frac{2^3}{12} -\frac{2^2}{2}+29*2 +c)\\S(6) -S(2) = 117.333\ gallons$

Rounded to the nearest gallon, the estimated total U.S. per capita sales of bottled water from the start of 2009 to the start of 2013 is 117 gallons.

6 0

3 years ago

Jana is doing an experiment. She is on a dock that is 10 feet above the surface of the water. Jana drops the weighed end of a fi

Pani-rosa [81]

To solve we have the following equation below,

Assumption: Line of reference is the surface of the water.

Final distance between Jana & fishing line = (dock height) +(reels out) -(reels back)

Final distance between Jana & fishing line = 10 + 35+ 29 - 7 = 67 feet

 ANSWER: 67 feet

7 0

3 years ago