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yarga [219]
4 years ago
12

tyler says that an equivalent expression for 2 exponent of 3 times 5 exponent is 10 exponent of 9 is he correct?

Mathematics
1 answer:
irakobra [83]4 years ago
6 0

Answer:

pls reword then i can help

Step-by-step explanation:

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What is the answer? 15 points
artcher [175]

Answer:

The third option.

8 0
2 years ago
A market analyst is hired to provide information on the type of customers who shop at a particular store. A random survey is tak
sveta [45]

Complete question:

A market analyst is hired to provide information on the type of customers who shop at a particular store. A random survey is taken of 100 shoppers at this store. Of these 100, 73 are women. The shoppers The data is summarized below. we grouped in three age categories, under 30, 30 up to 50 and 50 and over. Women under 30 are 30, Men under 30 are 8 Women 30 to 50 are 25 and Men are 14 Women 50 and over are 18 and Men are 5.

Let W be the event that a randomly selected shopper is a woman. Let A be the event that a randomly selected shopper is under 30. a.) Find the probability of W. W (women Shoppers) = Find the probability of A. b.) Find the probability of A and W. c.) P (A and W) (Shoppers) d.) Find the probability of A or W. P(A or W) (Shoppers) e.) Find the probability of A given W

Answer:

A) P(W) = 73/100; B) P(A) = 38/ 100 C) 30 / 100

D) 81/100 E) 30/73

Step-by-step explanation:

- - - - - - - - Women Men Total

Under 30 - - - 30 - - - 8 - - 38

30 to 50 - - - - 25 - - 14 - - 39

50 & over - - - 18 - - - 5 - - -23

Totals - - - - - - 73 - - -27 - - 100

Recall:

Probability : P= (required outcome / Total possible outcomes)

A) probability of women shoppers: P(W)

Number of women shoppers = 73; total shoppers = 100

P(W) = 73/100

B) Probability of under 30: P(A)

= number of shoppers under 30 = 38

Tital number of shoppers = 100

P(A) = 38/ 100

C) probability of A and W; This is the probability that the selected person is a woman and under 30.

(W n A) = 30

= 30 / 100

D) probability of A or W:

P(A) + P(W) - P(A n W) :

(38 / 100 + 73 / 100 - 30 / 100) = (38+73-30) /100

= 81/100

E) probability of A given W:

P(A n W) / P(W) = 30/73

5 0
3 years ago
The test scores of 40 students are listed below. Find P85.
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Answer:

Option A (89).

Step-by-step explanation:

Percentile is a statistic in which the an element at a certain percentage position is determined. To calculate the percentiles accurately, it is important that the data is present in the ascending order. Percentile is an important concept in data analysis. Interestingly, 50th percentile is the median of the data. The difference between the 75th and the 25th percentile is the interquartile range. To find the 85th percentile of the data, calculate 85% of 40, which is the number of elements in the data set. 40 * 85/100 = 34. The number on the 34th position is the 85th percentile of the data. It can be observed that 89 is on the 34th position. Therefore, Option A is the answer!!!

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a contractor uses the expression 7(x+3) to find the lenght,in feet,of chain that he needs for a certain project. Part A the cont
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Given that x is the number of chains;

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3 years ago
Which pair of triangles can be proved congruent by the SAS postulate?
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C. â–łADE and â–łEBA

Let's look at the available options and see what will fit SAS.

A. â–łABX and â–łEDX
* It's true that the above 2 triangles are congruent. But let's see if we can somehow make SAS fit. We know that AB and DE are congruent, but demonstrating that either angles ABX and EDX being congruent, or angles BAX and DEX being congruent is rather difficult with the information given. So let's hold off on this option and see if something easier to demonstrate occurs later.

B. â–łACD and â–łADE
* These 2 triangles are not congruent, so let's not even bother.

C. â–łADE and â–łEBA
* These 2 triangles are congruent and we already know that AB and DE are congruent. Also AE is congruent to EA, so let's look at the angles between the 2 pairs of congruent sides which would be DEA and BAE. Those two angles are also congruent since we know that the triangle ACE is an Isosceles triangle since sides CA and CE are congruent. So for triangles â–łADE and â–łEBA, we have AE self congruent to AE, Angles DAE and BEA congruent to each other, and finally, sides AB and DE congruent to each other. And that's exactly what we need to claim that triangles ADE and EBA to be congruent via the SAS postulate.
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3 years ago
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