The 400th term is 425.There are floor(√400) = 20 squares in the range 1..400, so the 400th term will be at least 420. There are floor(∛420) = 7 cubes in the range 1..400, so the 400th term may be as high as 427. However, there are
![\lfloor\sqrt[6]{427}\rfloor=2](https://tex.z-dn.net/?f=%5Clfloor%5Csqrt%5B6%5D%7B427%7D%5Crfloor%3D2)
numbers that are both squares and cubes. Consequently, the 400th term will be 427-2 =
425.
Answer:
Length x Width x Height
Step-by-step explanation:
Ok
First factor out the first 2 terms as follows:-
y = 1/2(x^2 - 8x) + 21
Now complete the square on x^2 - 8x:-
y = 1/2[ (x - 4)^2 - 16] + 21
y = 1/2(x - 4)^2 - 8 + 21
y = 1/2(x - 4)^2 + 13 Answer
Answer:
16
Step-by-step explanation:
a+ 3(b + c)
a + 3b + 3c
but a + 3b = 7 and c = 3
7+3(3)
7 + 9
=16