Answer:
the answer is A)no solutions
<span>B.
Linear function; the independent variable x is not an exponent.
But for me, answer is:
</span>
Linear function; <span>the function is in the form y = mx + b, where m = slope, b = y-intercept, and x is a real number.
</span>
Answer:
C
Step-by-step explanation:
Because its right
Answer:
a) 0.0167
b) 0
c) 5.948
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 6.16 ounces
Standard Deviation, σ = 0.08 ounces
We are given that the distribution of fill volumes of bags is a bell shaped distribution that is a normal distribution.
Formula:
a) Standard deviation of 23 bags
![\displaystyle\frac{S.D}{\sqrt{23}} = \frac{0.08}{\sqrt{23}} = 0.0167](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac%7BS.D%7D%7B%5Csqrt%7B23%7D%7D%20%3D%20%5Cfrac%7B0.08%7D%7B%5Csqrt%7B23%7D%7D%20%3D%200.0167)
b) P( fill volume of 23 bags is below 5.95 ounces)
P(x < 5.95)
Calculation the value from standard normal z table, we have,
c) P( fill volume of 23 bags is below 6 ounces) = 0.001
P(x < 6) = 0.001
Calculation the value from standard normal z table, we have,
![P( z \leq -3.09) = 0.001](https://tex.z-dn.net/?f=P%28%20z%20%5Cleq%20-3.09%29%20%3D%200.001)
![\displaystyle\frac{6 - \mu}{0.0167} = -3.09\\\\\mu = 6 + (0.0167\times -3.09) = 5.948](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac%7B6%20-%20%5Cmu%7D%7B0.0167%7D%20%3D%20-3.09%5C%5C%5C%5C%5Cmu%20%3D%206%20%2B%20%280.0167%5Ctimes%20-3.09%29%20%3D%205.948)
If the mean will be 5.948 then the probability that the average of 23 bags is below 6.1 ounces is 0.001.
Since there are 26 students in Mr. Carson's class, and each kid gets 3 pencils, that means we will multiply 26 and 3, in which we get 78. Now, since boxes of pencils only contain a dozen, which is 12 pencils, we will divide 78 by twelve, in which we get 6.5 boxes. You can't buy half a box, so he will need 7 boxes, since having 6 boxes means that you don't have enough pencils.
Hope this helps!