A theorem states that, given a circle with center C and a point P on the circumference, the tangent line through P and the radius CP are perpendicular.
So, the answer is 90 degrees.
Answer:
Step-by-step explanation:
Answer:
63.5
Step-by-step explanation:
The diagonals of a rhombus bisect opposite angles.
The longer diagonal bisects the 42° angle
The larger angle of the rhombus is 180 - 42 = 138
Let x = the length of the longer diagonal
You know two sides and the included angle of a triangle.
Using the law of cosines we get

x^2 = 34^2 + 34^2 - 2(34)(34) cos 138
= 1156 + 1156 - 2312 c0s 138
= 4030.1508...
x = sq rt 4030.1508...
= 63.5
2 x 10=20 60-20=40. 40 treats left