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Aleonysh [2.5K]
3 years ago
5

Patricia purchased x meters of fencing. She originally intended to use all of the fencing to enclose a square region, but later

decided to use all of the fencing to enclose a rectangular region with length y meters greater than its width. In square meters, what is the positive difference between the area of the square region and the area of the rectangular region?
Mathematics
1 answer:
sergejj [24]3 years ago
5 0

Answer:

  (y^2)/4 square meters

Step-by-step explanation:

For a perimeter length of x, the side of a square will be x/4 and its area will be (x/4)^2.

If one side of the square is shortened by y/2 and the adjacent side is lengthened by y/2, then the difference in side lengths will be y. The area of the resulting rectangle will be ...

  (x/4 -y/2)(x/4 +y/2) = (x/4)^2 -(y/2)^2

That is, the difference in area between the square and the rectangle is ...

  (x/4)^2 - ((x/4)^2 -(y/2)^2) = (y/2)^2 = y^2/4

The positive difference between the area of the square region and the area of the rectangular region is y^2/4 square meters.

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Answer:

Step-by-step explanation:

This is not nearly as threatening and scary as I first thought it was.  You must be in the section in Geometry where you are taught that perimeter of similar figures exist in a one-to-one relationship while areas of similar figures exist in a squared-to-squared relationship.  We will use that here.  

The area formula for a regular polygon is

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A=\frac{1}{2}(5.5055)(40)

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A = 110.11 units squared.

Here is where we can use what we know about similar figures and the relationships between perimeters and areas.  We will set up a proportion with the smaller polygon info on top and the larger info on bottom.  We know that the larger is 3 times the smaller, so the ratio of smaller to larger is

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Since perimeter is one-to-one and we know the perimeter of the smaller, we can create a proportion to solve for the perimeter of the larger:

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Cross multiply to get that the perimeter is 120 units.  You could also have done this by knowing that if the larger is 3 times the size of the smaller, then the side measure of the larger is 24, and 24 * 5 = 120.  But we used the way we used because now we have a means to find the area of the larger since we know the area of the smaller.

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\frac{s}{l}:\frac{1}{9}

Since we know the area for the smaller, we can sub it into a proportion and cross multiply to solve for the area of the larger.

\frac{s}{l} :\frac{1}{9} =\frac{110.11}{x}

A of the larger is 990.99 units squared

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The distance between Cincinnati, OH and Charlotte, North Carolina is about 336 miles. The distance between Cincinnati and Chicag
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Cincinnati Ohio à<span> Charlote North CA = a total of 336 miles
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