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amid [387]
4 years ago
11

What is the slope and y-intercept form of Y=3/2x+3

Mathematics
1 answer:
katovenus [111]4 years ago
3 0
3 over 2 is the slope and 3 is the y intercept. It’s already in the form.
You might be interested in
41) 124 students went on a field trip. Three
MrRissso [65]

Answer:

40 students on each bus

Step-by-step explanation:

If you subtract the 4 students that traveled by car from the total 124 students, you are left with 120 students riding the 3 buses. Then, you would divide 120 by 3. (120 students divided by 3 buses.)  120/3 = 40

7 0
3 years ago
Read 2 more answers
I need help! (HAPPY MLK DAY!!!)
olga2289 [7]

The slope and length of the given sides of the quadrilateral can be

found by using the coordinates of the vertices.

Correct responses:

  • Slope \ of \ \overline{IJ} = \underline{-\dfrac{7}{6} },      Length of \overline{IJ} = \underline{\sqrt{85} }
  • Slope \ of \ \overline{JK} = \underline {-\dfrac{2}{9}},     Length of \overline{JK} = \underline{\sqrt{85} }
  • Slope \ of \ \overline{KL} = \underline{-\dfrac{7}{6} },      Length of \overline{KL} = \underline{\sqrt{85}}
  • Slope \ of \  \overline{LI} = \underline{ -\dfrac{2}{9} },        Length of \overline{LI} = \underline{\sqrt{85} }

<h3>Methods used to find the slope and length of a line</h3>

The given coordinates of the vertices are;

K(-7, 0), J(2, -2), I(8, -9), L(-1, -7)

  • Slope = \mathbf{\dfrac{y_2 - y_1}{x_2 - x_1}}

  • Length \ of \ line =  \mathbf{ \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}}

Therefore;

Slope \ of \ \mathbf{\overline{IJ}} = \dfrac{-2 - (-9)}{2 - 8} = \dfrac{7}{-6} = \underline{ -\dfrac{7}{6}}

Length \ of \ \mathbf{\overline{IJ}} = \sqrt{(2 - 8)^2 + (-2 - (-9))^2} = \underline{\sqrt{85}}

Slope \  of \ \mathbf{\overline{JK}} = \dfrac{0 - (-2)}{-7 - 2}  = \dfrac{2}{-9} = \underline{-\dfrac{2}{9}}

Length \ of \ \mathbf{\overline{JK}} = \sqrt{(-7 - 2)^2 + (0 - (-2))^2}  = \underline{ \sqrt{85}}

Slope \ of \ \mathbf{\overline{KL}} = \dfrac{0 - (-7)}{-7 - (-1)} = \dfrac{7}{-6} = \underline{ -\dfrac{7}{6}}

Length  \ of \ \mathbf{\overline{KL} }= \sqrt{(-7 - (-1))^2 + (0 - (-7))^2} =\underline{ \sqrt{85}}

Slope \ of \ \mathbf{\overline{LI}} = \dfrac{(-9 - (-7))}{(8 - (-1))} = \dfrac{-2}{9} = \underline{-\dfrac{2}{9}}

Length \ of \ \mathbf{\overline{LI}} = \sqrt{(8 - (-1))^2 + (-9 - (-7))^2} = \underline{\sqrt{85}}

Learn more about finding the slope and length of a line here:

brainly.com/question/11612395

brainly.com/question/14039630

5 0
3 years ago
Solve the system of equations <br> y=x-2<br> x+y=10
nalin [4]

Answer:

Step-by-step explanation:

x + x - 2 = 10

2x - 2 = 10

2x = 12

x = 6

y = 6 -2

y = 4

(6,4)

6 0
4 years ago
PLZZ HELP ME 20 POINTS AND BRAINLIEST!
omeli [17]

Answer:

The price of price of the stock after it has been owned for 12 weeks is $92.55

Step-by-step explanation:

Given: The price of a particular stock is represented by the linear equation

y = -0.91x + 103.47

where x represents the number of weeks the stock has been owned and y represents the price of the stock, in dollars.

We have to find the price of price of the stock after it has been owned for 12 weeks.

Since , x represents the number of weeks the stock has been owned.

Thus, by substitute, x = 12

We get the value of y , the price of stocks.

Thus, y(x) =  -0.91x + 103.47

⇒ y(12) =  -0.91(12) + 103.47

⇒ y(12) =  -10.92 + 103.47

Solving , we get,

⇒ y(12) = 92.55

Thus, the price of price of the stock after it has been owned for 12 weeks is $92.55.

8 0
3 years ago
Read 2 more answers
PLEASE HELP FAST
gtnhenbr [62]

The correct answer is: D.) 6 7/8

Step-by-step explanation:

Given

2 3/4 divided 2/5

In order to divide two fractions, the reciprocal of the divisor is taken and then multiplied with the dividend.

So,

To solve

2\frac{3}{4} * \frac{5}{2}\\= \frac{11}{4} * \frac{5}{2}\\= \frac{55}{8}\\=6\frac{7}{8}

Hence

The correct answer is: D.) 6 7/8

Keywords: Fractions, division

Learn more about fractions at:

  • brainly.com/question/5102020
  • brainly.com/question/5069437

#LearnwithBrainly

5 0
4 years ago
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