Ok so we need to set the bottom to 0 to find the vertical asympyotes. This becomes x^2 - 4 = 0. Since we're talking about asymptotes, i'll assume you can solve basic equations. Solving for x and you get x = ±2. This means the vertical asymptotes are at ±2. To solve for horizontal asymptotes you take the limit as x goes to ±∞. Either way you end up with ±∞/∞. Now this isn't 1 because they grow at different rates. You differentiate both the top and bottom(L'hopital) and you get 6x/2x which becomes 3. This means the horizontal asymptote is at y = 3.
We know that, if in a distribution one tail is longer than the other, the distribution is skewed.
Here in the given histogram, it has a long right tail which is in the positive direction on the x axis. So it is right skewed distribution. That is also known as positive skewed distribution.
So here we have got the required answer. Option C is correct.
Answer:
The error is in step 3. You cannot use a property of logarithms to prove that same property.
Step-by-step explanation:
Here we the proof of the quotient rule as
If Logₐx = M and Logₐy = N
Then x = 
and y = 
x ÷ y = ÷ = 
Take log of both sides we get
Logₐ(x÷y) = Logₐ
Logₐ(x÷y) =M-N logₐa
Logₐ(x÷y) =M-N
∴Logₐ(x÷y) = Logₐx - Logₐy
Answer:
1/4 and in decimal form 0.25
Step-by-step explanation:
