Which statement is true about the extreme value of the given quadratic equation?

Mathematics

1 answer:

ICE Princess25 [194]3 years ago

3 0

Answer:

Option B. The equation has a maximum value with a y-coordinate of -21.

Step-by-step explanation:

The correct quadratic equation is

$y=-3x^{2}+12x-33$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

Convert to vertex form

Factor -3

$y=-3(x^{2}-4x)-33$

Complete the square

$y=-3(x^{2}-4x+2^2)-33+12$

$y=-3(x^{2}-4x+4)-21$

Rewrite as perfect squares

$y=-3(x-2)^{2}-21$

The vertex is the point (2,-21)

therefore

The equation has a maximum value with a y-coordinate of -21

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Alexeev081 [22]

Answer:

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3 years ago

How to turn a decimal into a fraction (im 12 soo could u D*mb it down in your explantion

Kisachek [45]

First off, I would like to say that you aren't d**b! Always remember that asking for help is never d**b!

To change a fraction to a decimal, put the decimal over its place value. For example, if you had the decimal 0.7, you would put 7 over 10 to create the fraction $\frac{7}{10}$ .