Question

Which statement is true about the extreme value of the given quadratic equation?

Answer 1

Answer:

Option B.  The equation has a maximum value with a y-coordinate of -21.

Step-by-step explanation:

The correct quadratic equation is

$y=-3x^{2}+12x-33$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

Convert to vertex form

Factor -3

$y=-3(x^{2}-4x)-33$

Complete the square

$y=-3(x^{2}-4x+2^2)-33+12$

$y=-3(x^{2}-4x+4)-21$

Rewrite as perfect squares

$y=-3(x-2)^{2}-21$

The vertex is the point (2,-21)

therefore

The equation has a maximum value with a y-coordinate of -21