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Sergeu [11.5K]
3 years ago
10

Which statement is true about the extreme value of the given quadratic equation?

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
3 0

Answer:

Option B.  The equation has a maximum value with a y-coordinate of -21.

Step-by-step explanation:

The correct quadratic equation is

y=-3x^{2}+12x-33

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

Convert to vertex form

Factor -3

y=-3(x^{2}-4x)-33

Complete the square

y=-3(x^{2}-4x+2^2)-33+12

y=-3(x^{2}-4x+4)-21

Rewrite as perfect squares

y=-3(x-2)^{2}-21

The vertex is the point (2,-21)

therefore

The equation has a maximum value with a y-coordinate of -21

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Find two positive numbers whose product is 36 and whose sum is a minimum.
alukav5142 [94]
Let one of the numbers be x. The other number cab then be represented as 36-x (x+36-x = 36).
The product can then be represented as y = x(36-x) or y=36x-x2

The maximum or minimum is always on the axis of symmetry which has the formula x=-b/2a.
In our case, the axis of symmetry is -36/-2, so x=18.

If one number is 18 and the 2 numbers add to 36, the other number is 18 as well.
So the 2 numbers are 18 and 18 and the maximum product is 324,
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