Answer:
y = 3(x+1)^2 - 4
Step-by-step explanation:The general form of the equation of a quadratic function whose vertex is (h,k) and whose leading coefficient is a is:
y - k = a(x-h)^2, or
y = a(x-h)^2 - k
Substituting the coefficients of the vertex (-1, -4), we get:
y = a(x + 1)^2 - 4
Substituting the coordinates of the given point, (1,8), we get:
8 = a(1+1)^2 - 4, which simplifies to:
8 = a(2)^2 - 4, or
8 = 4a - 4. Then 4a = 12, and a = 3.
Thus, the desired equation is y = 3(x+1)^2 - 4 (answer j).
18 2/5 = 92/5 = 18.4 as a decimal;
The exponential function that describes the graph is 
The standard form of an exponential function is expressed as 
a is the y-intercept
(x, y) is the point on the graph
Given the following expression
a = 7
(x, y) = (4, 112)
Substitute the given values into the exponential equation
![y = ab^x\\112=7\cdot b^4\\b^4 = \frac{112}{7}\\b^4= 16\\b =\sqrt[4]{16}\\b = 2](https://tex.z-dn.net/?f=y%20%3D%20ab%5Ex%5C%5C112%3D7%5Ccdot%20b%5E4%5C%5Cb%5E4%20%3D%20%5Cfrac%7B112%7D%7B7%7D%5C%5Cb%5E4%3D%2016%5C%5Cb%20%3D%5Csqrt%5B4%5D%7B16%7D%5C%5Cb%20%3D%202)
Get the required exponential equation
Recall that
, hence the required equation will be 
Learn more here: brainly.com/question/19245707