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Lana71 [14]
3 years ago
12

Find the points of intersection (if any) of the graphs of the equations. Use a graphing utility to check your results. y = - x +

4, y = 4x - 2

Mathematics
1 answer:
fredd [130]3 years ago
7 0

Answer:

x = 1.2

See Attachment for Graph

Step-by-step explanation:

Given

y = -x + 4

y = 4x - 2

Required

Determine the point of intersection

To do this, we simply equate both expressions of y

i.e.

-x + 4 = 4x - 2

Solve for x

-x - 4x =  - 2 - 4

-5x = -6

Divide through by -5

x = \frac{-6}{-5}

x = \frac{6}{5}

x = 1.2

<em>Hence, the point of intersection is 1.2</em>

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Answer:

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Need help ASAP! please help
Alisiya [41]

The missing angles in the triangle is as follows:

  • ∠1  = 62.5°
  • ∠2 = 62.5°
  • ∠3 = 55°
  • ∠4 = 75°
  • ∠5 = 50°

<h3>How to find the measure of angles in a triangle?</h3>

A triangle is a polygon with three sides. The sum of angles in a triangle is 180 degrees.

∠3 = 55 degrees (vertically opposite angles)

Vertically opposite angles are congruent to each other.

The exterior angle theorem states that the measure of an exterior angle is equal to the sum of the measures of the two remote interior angles of the triangle.

Using exterior angle theorem ,

105 = ∠5 + 55

∠5 = 105 - 55

∠5 = 50 degrees

∠4 = 180 - 50 - 55

∠4 = 75 degrees

Therefore, the other triangle is an isosceles triangle. This means the base angles are equal.

Hence,

∠1  = ∠2 = x

2x + 55 = 180

2x = 180 - 55

2x = 125

x = 125 / 2

x = 62.5 degrees.

Hence,

∠1  = ∠2 = 62.5 degrees.

learn more on angles here: brainly.com/question/28641859

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5 0
1 year ago
State the domain, the range, and the intervals on which function is increasing, decreasing, or constant in interval notation
aleksandr82 [10.1K]

Answer:

Domain: [-1,\infty)

Range: (-\infty, 3]

Decreases over: (-1,-\infty)

Step-by-step explanation:

Given

f(x) = -\sqrt{x + 1} + 3 --- Missing from the question

Solving (a): The domain

To get the domain, the expression under the square root must not be negative.

In other words:

x + 1 \ge 0

Solve for x

x + 1 -1\ge 0-1

x \ge -1

Hence, the domain is:

[-1,\infty)

To get the range, we plot the values of the domain in the expression.

x = -1

f(x) = -\sqrt{x + 1} + 3

f(-1) = -\sqrt{-1+1} +3

f(-1) = -\sqrt{0} +3

f(-1) = -0 +3

f(-1) = 3

x = \infty

f(\infty) = -\sqrt{\infty +1}+3

f(\infty) = -\sqrt{\infty}+3

f(\infty) = -\infty+3

f(\infty) = -\infty

So, the range is: (-\infty, 3]

To get the interval where the function increases or not, we simply plot the graph of f(x).

See attachment for graph.

From the attachment, it will be observed that the graph of f(x) continuously decreases from x = -1, and it never increased.

This implies that, the graph decreases over the interval (-1,-\infty)

6 0
3 years ago
Bill and Jenna are solving the quadratic equation x 2 - x = 12.
Stels [109]
X=-10 
by simplifying both sides of the equation then isolating the variable 
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