A)
8^2+9^2=c^264+81=c^2
c^2=145c=sqrt 145c=12.04
B)
Pythagerean Theorum:
A^2+B^2=C^2, where C is the hypotenuse and A and B are the other legs
15^2=9^2+B^2
225=81+B^2
225-81=B^2
144=B^2 (square root both sides)
12=B
To solve this, you’ll first need to solve for their slopes.
The slope for line Q is y2-y1/x2-x1 = -8-(-2)/-8-(-10) = -3
We know that the lines are perpendicular so the negative reciprocal of -3 is 1/3
The equation you get it y = 1/3x + b.
Now you will need to solve for b by substituting in the first ordered pair of line R.
2 = 1/3(1) + b.
Once you solve for b, you should get 5/3 and y = 1/3x + 5/3
Now, to find a, you will need to substitute in 10 from the second ordered pair into x in your new equation.
y = 1/3(10) + 5/3.
Your solution should be 5.
So your answer is: a = 5
2x+4(2x+7)+3(2x+4)
2x+8x+28+6x+12
16x+40
16x+40 would be the answer you can’t solve it any further
