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den301095 [7]
3 years ago
11

Errors in an experimental transmission channel are found when thetransmission is checked by a certifier that detects missing pul

ses.The number of errors found in a eight-bit byte is a random variablewith the following distribution:
F(x) = { 0 x<1
0.7 1 <= x < 4
0.9 4 <= x < 7
1 7 <= x

Determine each of the following probabilities:
(a) P(X <= 4) (b) P(X > 7)
(c) P(X <= 5) (d) P(X > 4)
(e) P(X <= 2)
Mathematics
1 answer:
Anastaziya [24]3 years ago
4 0

Answer:

a) P(X ≤ 4) = 0.9

b) P(X>7) = 0

c) P(X ≤ 5) = 0.9

d) P(X>4) = 0.1

e) P(X≤2)= 0.7

Step-by-step explanation:

Hello!

Given the distribution of cumulative probability

        0        for  X < 1

F(x)  0.7     for 1 ≤ X < 4

       0.9     for  4 ≤ X < 7

         1        for 7 ≤ X

To determine each of the asked probabilities you have to select the probability corresponding to the defined intervals for X:

a) P(X ≤ 4) = 0.9

This value of X is included the interval "4 ≤ X < 7" so the corresponding probability is 0.9

b) P(X>7) = 0

This is equal to the expression:

1 - P(X≤7)

This expression is included in the last interval so the probability is 1

1 - 1 = 0

c) P(X ≤ 5) = 0.9

5 is included in the third interval "4 ≤ X < 7" so the corresponding probability is 0.9

d) P(X>4) = 0.1

P(X>4) = 1 - P(X≤4)

P(X≤4) is in the interval of definition "4 ≤ X < 7" so the corresponding probability is 0.9

1 - 0.9 = 0.1

e) P(X≤2)= 0.7

The value X=2 is included in the second interval "for 1 ≤ X < 4", so the probability is 0.7

I hope it helps!

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tankabanditka [31]

Answer:

Arectangle=27.68cm (approximately)

Step-by-step explanation:

<em>in order to find the area of the rectangle first you need to find the measure of the length and width.</em>

since both of them aren't given ,use trigonometry to find the value of the length and width.

sin30°=opposite/hypotenuse

sin30°=opposite/8cm

opposite=sin30°*8cm. >sin30°=0.5

opposite=4cm

cos30°=adjacent/hypotenuse

cos30°=adjacent/8cm

adjacent=cos30°*8cm. cos30°=0.866

adjacent=6.92cm (approximate value)

Arectangle= bh

Arectangle=4cm*6.92cn

Arectangle=27.68cm

8 0
3 years ago
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Juli2301 [7.4K]

Answer:

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Step-by-step explanation:

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mote1985 [20]

Answer:

0

Step-by-step explanation:

Distance between two points is the slope .

Slope =change in y/change in x

Given (-26,0) and (95,0)

x1 = -26

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x2 = 95

y2 = 0

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4 0
4 years ago
an electronics company is designing a watch with a face that is in the shape of a hexagon and two congruent trapezoids attached.
nalin [4]

The total area of the face of the watch to the nearest tenth of a square centimemter is 9.0 cm²

Since an electronics company is designing a watch with a face that is in the shape of a hexagon and two congruent trapezoids attached. The heights of the trapezoids and the apothem of the hexagon measure 2 centimeters each, and the length of the shorter base of each trapezoid is 1.5 centimeters, the radii of the hexagon, and the base of the trapezoid form a triangle of

  • height, h = apothem of the hexagon = 2 cm and
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<h3>Area of the triangle</h3>

So, the area of this triangle is A = 1/2bh

= 1/2 × 1. 5 cm × 2 cm

= 1.5 cm × 1 cm

= 1.5 cm²

<h3>Area of the hexagon</h3>

Since there are 6 of such triangles in the hexagon, the area of the hexagon, A' = 6A

= 6 × 1.5 cm²

= 9.0 cm²

So, the total area of the face of the watch to the nearest tenth of a square centimemter is 9.0 cm²

Learn more about area of a hexagon here:

brainly.com/question/369332

5 0
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Answer:

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Step-by-step explanation:

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