Question

What is the product of the expressions? Assume y ≠ 0. (2y-1/y2)(3y2/7)

Answer 1

Answer:

(2y-1/y_2)(3y_2/7)

= 2y*(3y_2/7) - (1/y_2)(3y_2/7)

= 6y*y_2/7 - 3/7 = (6y*y_2 - 3)/7

Note: I'm not sure if the 2y-1 was written correctly. If it were intended as the entire thing being a numerator or as 2y_1, this answer is inaccurate.