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Alex73 [517]
3 years ago
5

Lily, Louis, and Ben went to an arcade and won tokens for prizes. Louis won 4.5 times as many tokens as Ben. Lily won 8 more tok

ens than Louis. Write an expression that describes how many tokens Lily won. Be sure to define any variables that you use.
Mathematics
1 answer:
lana66690 [7]3 years ago
7 0

<em><u>The expression that describes the number of tickets won by Lily is:</u></em>

a = 8 + 4.5c where "a" is the number of tokens won by Lily and "c" is the number of tokens won by Ben

<em><u>Solution:</u></em>

Given that Lily, Louis, and Ben went to an arcade and won tokens for prizes

Let "a" be the number of tokens won by Lily

Let "b" be the number of tokens won by Louis

Let "c" be the number of tokens won by Ben

<em><u>Given that Louis won 4.5 times as many tokens as Ben</u></em>

So we can frame a equation as:

number of tokens won by Louis =  4.5 times as many tokens as Ben

number of tokens won by Louis  = 4.5 x number of tokens won by Ben

b = 4.5 \times c

b = 4.5c

<em><u>Given that Lily won 8 more tokens than Louis</u></em>

number of tokens won by Lily = 8 + number of tokens won by Louis

a = 8 + b

Substituting the value of b = 4.5c in above expression

a = 8 + 4.5c

Thus the expression that describes how many tokens Lily won is found

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8/x-5 - 9/x-4 = 5/x^2-9x+20
adelina 88 [10]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2752942

_______________


Solve the equation:

\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}


Reduce the fractions at the left side so that they have the same denominator:

\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\&#10;\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\&#10;\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\&#10;\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}


Numerators must be equal:

\mathsf{8x-32-(9x-45)=5}\\\\&#10;\mathsf{8x-32-9x+45=5}\\\\&#10;\mathsf{8x-9x=5+32-45}\\\\&#10;\mathsf{-x=-8}\\\\&#10;\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}


I hope this helps. =)


Tags:  <em>rational equation fraction solution algebra</em>

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1+2=3. 4/10+2/10=6/10. 3+ 6/10=3 6/10
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