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3 years ago

11

A rectangle park has been constructed in downtown lilburn the designer wants to put a gravel walkway that cuts diagonally throug

h the park the width is 8ft and height is 6ft long what is the length of the walkway?

1 answer:

Nutka1998 [239]3 years ago

8 0

Answer:

10

Step-by-step explanation:

You might be interested in

Please help for bainlest

Natali [406]

Answer:

$\frac{5}{12}$

Step-by-step explanation:

$\frac{3}{4} -\frac{1}{3}$

Find the common denominator and multiply each side by that number

$\frac{9}{12} -\frac{4}{12}$

$\frac{5}{12}$

<u>For bolded part in explanation</u>: 4·3=12 3·3=9

3·4=12 1·4=4

4 0

3 years ago

the population of a city is 25,000. if the number of males is 240 more than the number of females, how many males and females ar

muminat

M=f+240

m+f=25000, using m from above in this equation gives you:

f+240+f=25000 combine like terms on left side

2f+240=25000 subtract 240 from both sides

2f=24760 divide both sides by 2

f=12380, and since m=f+240

m=12620

So there are 12620 males and 12380 females in the city.

6 0

3 years ago

Read 2 more answers

Matthew has a savings account that gives 1.5 interest. If he keeps it open for 5 years and it has a balance of 2000 how much in

pochemuha

Answer:

15187.5=2000(1.5)^5

Step-by-step explanation:

So right now he has 2000 in his saving each year it grows by 1.5 so by year 5 it should be

15187.5 in his savings

hope I did it right

6 0

3 years ago

QUESTION 9 OF 11

ivanzaharov [21]

Answer:

10

Step-by-step explanation:

sadasdasdasd

6 0

3 years ago

PLEASE HELP ME I'M GIVING 20PTS AND MARKING BRAINLIEST!!!!

pishuonlain [190]

Using a trigonometric identity, it is found that the values of the cosine and the tangent of the angle are given by:

$\cos{\theta} = \pm \frac{2\sqrt{2}}{3}$

$\tan{\theta} = \pm \frac{\sqrt{2}}{4}$

<h3>What is the trigonometric identity using in this problem?</h3>

The identity that relates the sine squared and the cosine squared of the angle, as follows:

$\sin^{2}{\theta} + \cos^{2}{\theta} = 1$

In this problem, we have that the sine is given by:

$\sin{\theta} = \frac{1}{3}$

Hence, applying the identity, the cosine is given as follows:

$\cos^2{\theta} = 1 - \sin^2{\theta}$

$\cos^2{\theta} = 1 - \left(\frac{1}{3}\right)^2$

$\cos^2{\theta} = 1 - \frac{1}{9}$

$\cos^2{\theta} = \frac{8}{9}$

$\cos{\theta} = \pm \sqrt{\frac{8}{9}}$

$\cos{\theta} = \pm \frac{2\sqrt{2}}{3}$

The tangent is given by the sine divided by the cosine, hence:

$\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}$

$\tan{\theta} = \frac{\frac{1}{3}}{\pm \frac{2\sqrt{2}}{3}}$

$\tan{\theta} = \pm \frac{1}{2\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}$

$\tan{\theta} = \pm \frac{\sqrt{2}}{4}$

More can be learned about trigonometric identities at brainly.com/question/24496175

#SPJ1

5 0

2 years ago