Let's solve for x.
−x+9y=−5
Step 1: Add -9y to both sides.
−x+9y+−9y=−5+−9y
−x=−9y−5
Step 2: Divide both sides by -1.
−x ÷ −1 = −9y−5 ÷ −1
x=9y+5
THE ANSWER FOR THE OTHER EQUATION: (x-5y=1)
Let's solve for x.
x−5y=1
Step 1: Add 5y to both sides.
x−5y+5y=1+5y
x=5y+1
Answer:
x=5y+1
I hope this helped I was a little confused on what your problem meant...so if this is not what you asked for just lmk so I can fix it for you :)
Answer:
-2 for both questions
Step-by-step explanation:
Length of side of the square = 2r
where r=radius of inscribed circle
Given an inscribed circle
Centre of circle , O(2,5)
Point on circle, P(-2,2)
Radius of circle
=distance OP
=sqrt((2-(-2))^2+(5-2)^2)
=sqrt(4^2+3^2)
=5
Therefore area of square
=(2r)^2
=(2*5)^2
=10^2
=100
I think 36,now don't trust me fully
Answer:
A function of f is continuous on its domain if it is Dirichlet function
