The answer to this is 2. Ten only has two factors, 5 and 2, and 2 can be decided evenly amongst them all.
The easiest way to do this is to plug in the numbers for the variebles and see if they equal the same in both sides. lets try the first one 5(1)+2(-3)=-1, multiply the nmbers to get 5-6=-1 now simplify to get the answer of -1=-1, they both equal the same so this means that the first option is the correct one
Hope this helps
Solve by substitution
Just plug in y=-x-1 into y+x=3
So we get:
Simplify that:
And since that is not true, that means this system of equations has no solutions!
3x - y = 9
y = -2x + 11
3x - (-2x + 11) = 9
3x + 2x - 11 = 9
3x + 2x = 9 + 11
5x = 20
x = 20/5
x = 4
y = -2x + 11
y = -2(4) + 11
y = -8 + 11
y = 3
solution (where the lines intersect) is (4,3)
Answer:
There are (63) combinations. The notation means "six choose three". Out of six items (flavors) choose three.
(nk)=n!k!(n−k)!.
(63)=6!3!3!.
Think of it this way. There are 6 ways to choose a flavor. Once you choose, there are 5 ways to choose the next. After that, there are 4 flavors left. which is 6!/3!=6⋅5⋅4⋅3⋅2⋅13⋅2⋅1=6⋅5⋅4=120.
But, you could have chosen {chocolate,vanilla,strawberry} and you get the same combination as {vanilla, strawberry, chocolate} so we have to divide by 3!=3⋅2⋅1=6 to account for the order of choosing.
So the number of combinations of flavors is (63)=1206=20.
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