Find the area of a polygon with the given vertices J(-3,4) K(4,4) L(3,-3)
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<h2>Given:-</h2><h3>perimeter of rectangle=26cm</h3><h3>Area of rectangle=>30cm²</h3><h3>{•°• perimeter of rectangle=2(l+b) }</h3><h3>{•°•. Area of rectangle=lxb}</h3><h3>So, 2(l+b)=26</h3><h3> =>(l+b)=26/2</h3><h3> =>l+b=13</h3><h3> =>l=(13-b) ----------(1)</h3><h3>Again,</h3><h3> =>lxb=30</h3><h3> =>(13-b)xb=30 {putting the value of l from equation 1}</h3><h3> </h3><h3> =>13b-b²=30</h3><h3> =>b²-13b+30=0</h3><h3> =>b²-10b-3b +30=0</h3><h3> =>b(b-10)-3(b-10)=0</h3><h3> =>(b-10)(b-3)=0</h3><h3> </h3><h3>or,</h3><h3> =>b=10 or b=3</h3><h3>putting the value of b in equation (1)</h3><h3> =>l=(13-b)</h3><h3> =>l=13-10=3 { taking b=10}</h3><h3> =>l=13-3=10 { taking b=3}</h3><h3>Hence, length=3 when breadth=10</h3><h3> length=10 when breadth=3</h3><h3>•take care</h3><h3>°mark as brainlist please</h3><h3>•follow me</h3>✌️✌️
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