Ask question

Ask question

All categories

2 years ago

14

Question 61 point)

1 answer:

Natasha_Volkova [10]2 years ago

7 0

45 I think is the answer

You might be interested in

Please hurry! This is due soon.

kotykmax [81]

Hi!

We can see here that this is a composition question.

And since the composition of g of f of x is x, we can conclude that g(x) is the inverse of f(x) (if you're confused, search up the definition of an inverse function).

To find an inverse function, we can take the f(x) function and change the positions of the x and y variables.

$f(x)=\frac{e^7^x+\sqrt{3}}{2}$

$y=\frac{e^7^x+\sqrt{3}}{2}$

$x=\frac{e^7^y+\sqrt{3}}{2}$

$2x=e^7^y+\sqrt{3}$

$e^7^y=2x-\sqrt{3}$

$7y=ln(2x-\sqrt{3})$

$y=\frac{ln(2x-\sqrt{3})}{7}$

Which is answer choice A, to check your work, you can solve the composition of g(f(x)), which will get you x.

$g(f(x))$

$g(\frac{e^7^x+\sqrt{3}}{2})$

$\frac{ln(2(\frac{e^7^x+\sqrt{3}}{2})-\sqrt{3}}{7}$

2s cancel.

$\frac{ln(e^7^x+\sqrt{3})-\sqrt{3}}{7}$

The natural log and e cancel.

$\frac{7x+\sqrt{3}-\sqrt{3}}{7}$

$\sqrt{3}$ s cancel.

$\frac{7x}{7}$

7s cancel.

$x$

Hope this helps!

3 0

2 years ago

If there were to be 9 boys and 6 girls at a party and the host wanted each to be given the same number of candies that could be

VARVARA [1.3K]

I got 5 packages as the answer

7 0

3 years ago

Finding volume of a rectangular prism

torisob [31]

Answer:

uhh.... you are missing some part of your question

Step-by-step explanation:

6 0

2 years ago

Music Co charges a fee of $20 a month plus $1 per song Jams charges no monthly fee but $3 per song. How many songs would have to

NeTakaya

Answer:

10 songs

Step-by-step explanation:

20 + 1x = 3x

20 = 2x

10 = x

—

20 + 1(10) = 3(10)

20 + 10 = 30

30 = 30

4 0

2 years ago

(i) 3 (a + 5b) + a (a + 4) (ii) y (10 - y) + 3 (y - 2) (iii) 2 (8a - 5b) + 3 (5a - 12) (iv) 3 (y - 3) + ( 8 - 6y + x) (v) a (a -

AveGali [126]

Answer:

$3 (a + 5b) + a (a + 4) = a^2 + 7a + 15b$

$y (10 - y) + 3 (y - 2) = - y^2+13y - 6$

$2 (8a - 5b) + 3 (5a - 12) = 31a -10b - 36$

$3 (y - 3) + ( 8 - 6y + x) = -3y + x-1$

$a (a - 2b) + b (b + 2a - c) =a^2 + b^2 - bc$

$5 (x - y + z) + (4x + 3y) =9x - 2y +5z$

Step-by-step explanation:

Solving (i):

$3 (a + 5b) + a (a + 4)$

Open brackets

$3 (a + 5b) + a (a + 4) = 3a + 15b + a^2 + 4a$

Collect like terms

$3 (a + 5b) + a (a + 4) = a^2 + 4a+3a + 15b$

$3 (a + 5b) + a (a + 4) = a^2 + 7a + 15b$

Solving (ii)

$y (10 - y) + 3 (y - 2)$

Open bracket

$y (10 - y) + 3 (y - 2) = 10y - y^2 + 3y - 6$

Collect like terms

$y (10 - y) + 3 (y - 2) = - y^2+10y + 3y - 6$

$y (10 - y) + 3 (y - 2) = - y^2+13y - 6$

Solving (iii)

$2 (8a - 5b) + 3 (5a - 12)$

Open bracket

$2 (8a - 5b) + 3 (5a - 12) = 16a -10b + 15a - 36$

Collect like terms

$2 (8a - 5b) + 3 (5a - 12) = 16a+ 15a -10b - 36$

$2 (8a - 5b) + 3 (5a - 12) = 31a -10b - 36$

Solving (iv)

$3 (y - 3) + ( 8 - 6y + x)$

Open bracket

$3 (y - 3) + ( 8 - 6y + x) = 3y - 9 + 8 - 6y + x$

Collect like terms

$3 (y - 3) + ( 8 - 6y + x) = 3y - 6y + x- 9 + 8$

$3 (y - 3) + ( 8 - 6y + x) = -3y + x-1$

Solving (v):

$a (a - 2b) + b (b + 2a - c)$

Open bracket

$a (a - 2b) + b (b + 2a - c) =a^2 - 2ab + b^2 + 2ab - bc$

Collect like terms

$a (a - 2b) + b (b + 2a - c) =a^2 + 2ab- 2ab + b^2 - bc$

$a (a - 2b) + b (b + 2a - c) =a^2 + b^2 - bc$

Solving (vi)

$5 (x - y + z) + (4x + 3y)$

Open brackets

$5 (x - y + z) + (4x + 3y) =5x - 5y +5z+4x +3y$

Collect like terms

$5 (x - y + z) + (4x + 3y) =5x +4x +3y- 5y +5z$

$5 (x - y + z) + (4x + 3y) =9x - 2y +5z$

6 0

2 years ago