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fiasKO [112]
3 years ago
14

Question 61 point)

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
7 0
45 I think is the answer
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The points (0 1) and (1 4) are contained in the graph of an equation with only two variables x and y
Blababa [14]

The line that passes through (0 1) and (1 4) is a linear equation

The equation of the points is y = 3x + 1

<h3>How to determine the equation of the points?</h3>

The points are given as:

(x,y) = (0 1) and (1 4)

Start by calculating the slope (m)

m = (y₂ - y₁)/(x₂ - x₁)

So, we have:

m = (4 - 1)/(1 - 0)

Evaluate

m = 3

The equation is then calculated as:

y = m(x - x₁) + y₁

This gives

y = 3(x - 0) + 1

Evaluate the product

y = 3x + 1

Hence, the equation of the points is y = 3x + 1

Read more about linear equations at:

brainly.com/question/1884491

7 0
2 years ago
Please help for 50 points...
vaieri [72.5K]

Answer:

7. ○ ∆<em>ACB</em> ≅ ∆<em>DFE</em>

6. ○ \displaystyle 43°

5. ○ \displaystyle ∠M ≅ ∠S

4. ○ \displaystyle octagon

3. ○ \displaystyle squares

2. ○ \displaystyle rhombus

1. ○ \displaystyle equilateral\:triangle

Step-by-step explanation:

7. Everything is in correspondence with each other, so just follow the pattern in the order the they were originally.

6. All angles correspond with each other, so just follow the pattern.

5. All segments and angles correspond with each other, so just follow their patterns.

4. An <em>octagon</em><em> </em>has eight sides, a triangle has three sides, a <em>hexagon</em> has six sides, and a <em>pentagon</em><em> </em>has five sides. With this being stated, you have your answer.

3. In a previous lesson, we confirmed that <em>all squares </em><em>are</em><em> </em><em>rectangles</em><em> </em>because it is a quadrilateral with four right angles.

2. This is obviously a rhombus because it is a quadrilateral with four congruent angles and sides.

1. An EQUILATERAL TRIANGLE is a regular polygon because they have three congruent angles and sides.

I am joyous to assist you anytime.

4 0
3 years ago
Read 2 more answers
Suppose you are given information about a triangle according to SSS, SAS, and ASA. For which of these can you immediately use th
jek_recluse [69]

Answer:

SSS and SAS

Step-by-step explanation:

Law of cosines: The law of cosines is used for calculating one side of a triangle when the angle opposite and the other two sides are known.

If the information about a triangle according to SSS, SAS and ASA is given, then we will immediately use SSS and SAS  by using the law of cosines to find one of the remaining measures because Law of cosines is applied if we know one angle opposite and the other two sides.

Also, in ASA, we know two angles and one side, thus we cannot use Law of cosines in this, rather Law of sines can be accurately use in this case.

if you have two sides, encroaching an angle, then the Law of Cosines can be used to find a missing side, thus SAS will work fine for that, now, if you have no angles given, but you know all sides, you can use the Law of Cosines as well, by solving it for the angle, and get the angles, on which case, SSS will do... .now as far as ASA, if you have two angles and one side known, then... that's not very workable for the law of cosines

please mark me brainliest :)

3 0
3 years ago
Read 2 more answers
NO LINKS!! Please help me with these notes. Part 1a​
erik [133]

Answers:

When we evaluate a logarithm, we are finding the exponent, or <u>    power   </u>  x, that the  <u>   base   </u> b, needs to be raised so that it equals the <u>  argument   </u> m. The power is also known as the exponent.

5^2 = 25 \to \log_5(25) = 2

The value of b must be <u>   positive    </u> and not equal to <u>   1   </u>

The value of m must be <u>   positive   </u>

If 0 < m < 1, then x < 0

A <u>   logarithmic  </u>    <u>   equation  </u> is an equation with a variable that includes one or more logarithms.

===============================================

Explanation:

Logarithms, or log for short, basically undo what exponents do.

When going from 5^2 = 25 to \log_5(25) = 2, we have isolated the exponent.

More generally, we have b^x = m turn into \log_b(m) = x

When using the change of base formula, notice how

\log_b(m) = \frac{\log(m)}{\log(b)}

If b = 1, then log(b) = log(1) = 0, meaning we have a division by zero error. So this is why b \ne 1

We need b > 0 as well because the domain of y = log(x) is the set of positive real numbers. So this is why m > 0 also.

5 0
2 years ago
Help ill give brainlist
Rom4ik [11]

Answer:

1) C. 4

2) A. c=4m

(give me brainly if im right pls)

3 0
3 years ago
Read 2 more answers
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